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3 years ago

What is the equation of the quadratic graph with a focus of (1,1) and a directrix of y=-1

1 answer:

7 0

Ok the vertex is the midpoint of the line between the focus and directrix so it is (1, 0) and the constant before is equal to 1/4 I believe so the equation should be y= 1/4 * (x-1)^2

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RS=2x-8, ST = 11, RT = x+10

ziro4ka [17]

Answer:

$Equation~=~\Large\boxed{2x+3=x+10}$

$x~=~\Large\boxed{7}$

$RS~=~\Large\boxed{6}$

$RT~=~\Large\boxed{17}$

Step-by-step explanation:

Given information

$RS=2x-8$

$ST=11$

$RT=x+10$

Derived expression from the given information

Presumably, I think this is a combination of segments

$RS+ST=RT$

Substitute values into the given expression

$(2x-8)+(11)=(x+10)$

Combine like terms

The following is the expression

$\Large\boxed{2x+3=x+10}$

Subtract 3 on both sides

$2x+3-3=x+10-3$

$2x=x+7$

Subtract x on both sides

$2x-x=x+7-x$

$\Large\boxed{x=7}$

Substitute the x value into corresponding expressions to determine the final value

$RS=2x-8=2(7)-8=14-8=\Large\boxed{6}$

$RT=x+10=(7)+10=\Large\boxed{17}$

Hope this helps!! :)

Please let me know if you have any questions

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