What is the equation of the quadratic graph with a focus of (1,1) and a directrix of y=-1

1 answer:

7 0

Ok the vertex is the midpoint of the line between the focus and directrix so it is (1, 0) and the constant before is equal to 1/4 I believe so the equation should be y= 1/4 * (x-1)^2

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I went shopping for a pencil case with the entire script of shrek with an onion zipper, which costed 2.50$ each pencil case. I h

scZoUnD [109]

Answer:

40 pencil cases

Step-by-step explanation:

To find out how many $2.50 pencil cases you can buy with $100, you need to divide. Dividing the amount of money you have by the cost of the item will get you the amount of items you can buy. 100 divided by 2.50 is 40. So, you can get 40 cases.

4 0

3 years ago

9) Twenty-seven (27) months is months less than 3 years. Termain Fonhniene

azamat

Answer:

Decimal answer: 0.75 months. Fraction answer: 3/4

Step-by-step explanation: You have to make the 27 months into years, which is 2.25 years. Then subtract 2.25 from 3 and it equals 0.75.

4 0

2 years ago

For the function given state the period f(t) =6sin(3t-pi/6)-1

lapo4ka [179]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}

\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now, with that template in mind, let's take a peek at yours

$\bf \begin{array}{lllcclll}
f(t)=&6sin(&3t&-\frac{\pi }{6})&-1\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
period\qquad \cfrac{2\pi }{B}\iff\cfrac{2\pi }{3}$

8 0

3 years ago

I lost all my points and answers so heres 25 for whoever wants it

TEA [102]

Hello thank you thanks

5 0

3 years ago

Oscar invests $20,000 in three investments earning 6% ,8% and 10%. He invests $9000 more in the 10% investment than in the 6% in

Hatshy [7]

This problem is mainly concerned with setting up an equation.

let's add the interest rates times their respective investment amounts:

$a = (9000 + x)0.10$

$b = x \times 0.06$

$c=(20000 - ((9000 + x) + x)) 0.08$

simplify:

$c = (11000 - 2x) \times 0.08$

sum of interest:

$1780 = a + b + c$

1780 = (9000+x) 0.10 + x 0.06 + (11000-2x)0.08

$1780 = 1780 + 0 \times x$

$0=0$

solution:

He does not have any invested in the 6%, while he has 9000 invested at 10% and 11,000 invested at 8%

to check:

$9000 \times 0.10 + 11000 \times 0.08$

$= 900 + 880 = 1780$

So this ended up being a trick problem because he does not actually have any invested in the 6% option.

6 0

3 years ago