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zimovet [89]
2 years ago
8

40x + 44 = 38x + 44​

Mathematics
2 answers:
Mila [183]2 years ago
8 0

Answer:

x = 0

Step-by-step explanation:

40(0) + 44 = 38(0) + 44

44 = 44

When x = 0 the equation is true

vovangra [49]2 years ago
4 0

Answer:

x=no solution

Step-by-step explanation:

40x+44=38x+44

-44          -44

40x=38x

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aleksklad [387]
80,000 per year....there are 12 months in a year

80,000 / 12 = 6666.67 per month
6 0
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I WILL NAME YOU BRAINLIEST AND GIVE YOU ALL MY POINTS IF YOU SOLVE THIS!!!!! In the diagram, each shape has a value and the sums
cluponka [151]

Answer:

...

Step-by-step explanation:

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7 0
3 years ago
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Homework help, no need to explain answer
Ainat [17]

Answer:

Square each side

Subtract 1  from each side

Divide by 3

Step-by-step explanation:

sqrt(3x+1) = 4

Square each side

(sqrt(3x+1))^2 = 4^2

3x+1 = 16

Subtract 1  from each side

3x+1-1 = 16-1

3x= 15

Divide by 3

3x/3 = 15/3

x = 5

8 0
3 years ago
What is the vertex of the quadratic function f(x)=x2+6x+16? Write your answer
Olenka [21]

Answer:

The vertex of the quadratic function is:

(x_{v}, y_{v})=\left(-3,\:7\right)

Step-by-step explanation:

Given the function

f\left(x\right)=x^2+6x+16

As the vertex of the form y=ax^2+bx+c is defined as:

x_v=-\frac{b}{2a}

As the quadratic function of parabola params are

a=1,\:b=6,\:c=16

so

x_v=-\frac{b}{2a}

x_v=-\frac{6}{2\cdot \:1}

x_v=-3

Putting x_v=-3 to determine y_v

y_v=\left(-3\right)^2+6\left(-3\right)+16

y_v=3^2-18+16

y_v=9-2

y_v=7

Therefore, the vertex of the quadratic function is:

(x_{v}, y_{v})=\left(-3,\:7\right)

5 0
3 years ago
Last month, Katie started training for the swim team. She swam 20 laps every day for 18 training days. This month, Katie wants t
nasty-shy [4]

She swim 20 laps every day for 18 training days

so total laps done last month = 20*18 = 360 laps

She will swim 3 more laps per training day and add more training days to her monthly schedule.

20 laps + 3 laps = 23 laps

(a)If Katie adds 5 training days to her schedule this month, will she swim 215 more laps?

18 days + 5 days more = 23 days

23 laps every day for 23 training days

so total laps = 23*23 = 529 laps. That is 169 more laps than 360 laps done last month. Hence she cannot swim 215 more laps

If Katie adds 10 more training days to her schedule this month, will she swim 215 more laps?

18 days + 10 days more = 28 days

23 laps every day for 28 training days

so total laps = 23*28 =644 laps. That is 284 more laps than 360 laps done last month. Hence she can swim 215 more laps

(c)If Katie adds 6 more training days to her schedule this month, will she swim 215 more laps?

18 days + 6 days more = 24 days

23 laps every day for 24 training days

so total laps = 23*24 =552 laps. That is 192 more laps than 360 laps done last month. Hence she cannot swim 215 more laps

Build an equation for finding the number of additional training days she needs to swim 215 more laps

Let x be the number of days more

So training days = 18 + x

215 more laps , so total laps = 360 + 215 = 575

3 more laps per training day so 20 + 3 = 23 laps per day

laps * training days = total laps

so equation becomes

23 * (18+x) = 575

Now solve for x

414 + 23x = 575

Subtract 414 from both sides

23x = 161

x= 7

so she needs 7 training days to swim 215 more laps

3 0
3 years ago
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