Can somebody please solve this? I'm confused
1 answer:
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Answer:
A) 8
Step-by-step explanation:
Mean weight = u = 25 pounds
Standard Deviation = = 4 pounds
We have to find how many beagles out of 75 will weigh more than 30. Since the data is normally distributed, we can use z score to find this value. First we will what is the percentage(probability) of a randomly selected beagle to weigh more than x = 30 pounds, using this percentage we can then find our answer.
The formula for z score is:
Using the values, we get:
So, P(Weight > 30) is equivalent to P(z > 1.25). Using the z table, we can write:
P(z > 1.25) = P(Weight > 30) = 0.1056
This, 0.1056 or 10.56% of the beagles are expected to weigh more than 30 pounds.
So,out of 75 beagles, 10.56% of 75 are expected to weigh more than 30 pounds.
10.56% of 75 = 0.1056 x 75 = 7.92 = 8 (rounding to nearest integer)
Therefore, out of 75 beagles 8 are expected to weigh more than 30 pounds.