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Romashka [77]
3 years ago
11

v A square garden has an area of 110 square feet. a. What is the approximate length of one side of the garden? Round to the near

est tenth.
Mathematics
1 answer:
tankabanditka [31]3 years ago
8 0
Idkdkdndmnebebebwbwwjwo
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Please help me right know! Fill in the blanks
bagirrra123 [75]
I don’t understand what you are asking for
6 0
3 years ago
Find the next 2 terms in the Geometric sequence 20,30,45 ...
DochEvi [55]

Answers:

The next two terms are 67.5 and 101.25 in that order.

===========================================

Explanation:

Divide the second term over the first to get 30/20 = 1.5

Divide the third term over the second term to get 45/30 = 1.5

The common ratio is 1.5, which means we multiply 1.5 by each term to get the next term

-------

fourth term = 1.5*(third term) = 1.5*45 = 67.5

fifth term = 1.5*(fourth term) = 1.5*67.5 = 101.25

-------

As a shortcut you can plug n = 4 and n = 5 into the function t(n) = 20*(1.5)^(n-1) to get the fourth and fifth terms respectively.

3 0
3 years ago
I need this question sovled asap y=200x+35,000
Svetradugi [14.3K]

Answer: look at the picture

Step-by-step explanation: Hope this help :D

6 0
3 years ago
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
2 years ago
Add: 7/8 + 5/6 .......
Rashid [163]

Answer:

1 17/24

Step-by-step explanation:

To add fractions, find the LCD and then combine.

Exact Form:

41/24

Decimal Form:

1.7083

Mixed Number Form:

1 17/24

6 0
3 years ago
Read 2 more answers
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