All categories

2 years ago

Please please help ! Thank you

Mathematics

1 answer:

miskamm [114]2 years ago

4 0

Answer:

4/3c^4 -it wont let me put it as it shows on your screen but the 4 is on top and under the line is 3c^4,

Step-by-step explanation:

Cancel the common factor of c^3 and z^7 -im not sure if this is what you were trying to get but its a answer-

You might be interested in

I need the answer fast please

Rainbow [258]

Substitute each value of x in y=2x-3

so,

first box (-2)
y= 2(-2)-3
y= -4-3
y= -7

second box (0)
y= 2(0)-3
y= 0-3
y= -3

third box (3)
y=2(3)-3
y=6-3
y=3

6 0

2 years ago

Read 2 more answers

Let $DEF$ be an equilateral triangle with side length $3.$ At random, a point $G$ is chosen inside the triangle. Compute the pro

umka21 [38]

$|\Omega|=(\text{the area of the triangle})=\dfrac{a^2\sqrt3}{4}=\dfrac{3^2\sqrt3}{4}=\dfrac{9\sqrt3}{4}\\|A|=(\text{the area of the sector})=\dfrac{\alpha\pi r^2}{360}=\dfrac{60\pi \cdot 1^2}{360}=\dfrac{\pi}{6}\\\\\\P(A)=\dfrac{\dfrac{\pi}{6}}{\dfrac{9\sqrt3}{4}}\\\\P(A)=\dfrac{\pi}{6}\cdot\dfrac{4}{9\sqrt3}\\\\P(A)=\dfrac{2\pi}{27\sqrt3}\\\\P(A)=\dfrac{2\pi\sqrt3}{27\cdot3}\\\\P(A)=\dfrac{2\pi\sqrt3}{81}\approx13.4\%$

8 0

3 years ago

Read 2 more answers

find the surface area of a right regular hexagonal pyramid with sides 3 cm and slant heights 6cm. show all of your work.

DedPeter [7]

Answer:

The surface area of right regular hexagonal pyramid = 82.222 cm³

Step-by-step explanation:

Given as , for regular hexagonal pyramid :

The of base side = 3 cm

The slant heights = 6 cm

Now ,

The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}$

Where a is the base side

And h is the slant height

So, The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}$

Or, The surface area of right regular hexagonal pyramid = $\frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}$

Or, The surface area of right regular hexagonal pyramid = 23.38 + 9 × $\frac{171}{4}$

∴ The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538

I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842

So, The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer

6 0

3 years ago

This question is from Apex: Algerba 1 Sem 2: 3.5.3 Quiz (PLEASE HELP! Thanks)

Radda [10]

Answer:A

Step-by-step explanation:

3 0

2 years ago

Set up the trig equation with the correct values plugged in that you would use to solve for h. (You do not need to solve)

Usimov [2.4K]

From the reference of the 18 degree angle, 'h' is the opposite side and 100 is the adjacent side.

The trig ratio which uses both the opposite and adjacent sides is the tangent.

tan(18) = opp/adj = h/100

Trig equation:
tan(18) = h/100

3 0

3 years ago