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konstantin123 [22]
3 years ago
14

Find the area. 7 in. 5 in. 12 in.

Mathematics
1 answer:
vitfil [10]3 years ago
6 0

Answer and Step-by-step explanation:

<u>The area formula for a trapezoid is as follows:</u>

A = \frac{a + b}{2}h

Where:

A = Area

a = top side length

b = bottom side length

h = height

<u>Plug in the values given to you into the equation and solve.</u>

A = \frac{7 +12}{2}(5)

A = \frac{19}{2}(5)

A = \frac{95}{2}

<u>A = 47.5 </u>in.^2<u> is the answer.</u>

<u></u>

<em><u>#TeamTrees #PAW (Plant And Water) #ALM (All Lives Matter)</u></em>

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1) Suppose a rhombus has 12 cm sides and a 30° angle. Find the distance between the pair of opposite sides.
Sergeeva-Olga [200]

Answer:

1) 6 cm

2) 117°

Step-by-step explanation:

1) Draw a picture of the rhombus.  The distance between opposite sides is the height of the rhombus.  If we draw the height at the vertex, we get a right triangle.  Using trigonometry:

sin 30° = h / 12

h = 12 sin 30°

h = 6 cm

2) Draw a picture of the rectangle.

∠KML is the angle the diagonal makes with the shorter side ML.  This angle is 54°.  ∠NKM is the angle the diagonal makes with the shorter side NK.  ∠KML and ∠NKM are alternate interior angles, so m∠NKM = 54°.

The angle bisector of angle ∠NKM divides the angle into two equal parts and intersects the longer side NM at point P.  So m∠PKM = 27°.

KLMN is a rectangle, so it has right angles.  That means ∠KML and ∠KMN are complementary.  So m∠KMN = 36°.

We now know the measures of two angles of triangle KPM.  Since angles of a triangle add up to 180°, we can find the measure of the third angle:

m∠KPM + 36° + 27° = 180°

m∠KPM = 117°

7 0
3 years ago
How do i solve for this?
vekshin1
For one set the two equations equal to eachother and solve from there. 2 is 45
For three set the two equations equal. Same for four
6 0
2 years ago
What are the intercept(s) of ƒ(x) = x2?
IgorC [24]
There are no intercepts. (o,o)
4 0
3 years ago
_________ is the quality a design has if it maintains all characterics when it is rotated about a point lying in its plane.
nekit [7.7K]

Answer:

B.) Rotational Symmetry


4 0
3 years ago
Read 2 more answers
How many and what type of solutions does the equation have?
Natali [406]
Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0

As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
Δ<u /> = 81

Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2

So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2

A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.

3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.

So 2k^2 = 9 + 3k have two rational solutions (Option B).

Hope this Helps! :)
7 0
3 years ago
Read 2 more answers
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