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ololo11 [35]
2 years ago
13

I will mark u brainliest please help

Mathematics
2 answers:
musickatia [10]2 years ago
6 0

Answer:

30+(2x+7)+63=180(sum of angles of triangle )

30+2x+7+63=180

2x+100=180

2x=180-100

x=80/2

x=40

ELEN [110]2 years ago
4 0

Answer:

\boxed {\boxed {\sf (2x+7)+30+63= 180}}

\boxed {\boxed {\sf x=40}}

Step-by-step explanation:

We are asked to write an equation to solve for x and use the equation to find x.

We know that the angles in a triangle must add to 180 degrees. Therefore, the sum of the three angles in this triangle: 30, 63, and (2x+7) must equal 180. We can set up an equation.

(2x+7)+ 30 +63= 180

Now we can use the equation to solve for x. First, we combine like terms on the left side of the equation. The 3 terms without variables or constants can be added.

2x+ (7+30+63)= 180

2x+ (100)= 180

We are solving for x, so we must isolate the variable. 100 is being added to 2x. The inverse operation of addition is subtraction. Subtract 100 from both sides of the equation.

2x+100-100= 180-100 \\2x=180 -100 \\2x=80

x is being multiplied by 2. The inverse operation of multiplication is division. Divide both sides of the equation by 2.

\frac {2x}{2}= \frac{80}{2}

x= \frac {80}{2} \ \\

x=40

The equation is (2x+7)+ 30+63= 180 and x is equal to 40.

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Yuri [45]

Preston and Horacio have 49 video games horacio has 11 more games than Preston how many games does each person have

49 - 11 = 38.

38/2 = 19.

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Ivanshal [37]

The average rate of change of function g(x)=5(2)^{x} from x = 3 to x = 4 is 4 times that from x = 1 to x = 2.

The correct option is (A).

What is the average rate of change of a function?

The average rate at which one quantity changes in relation to another's change is referred to as the average rate of change function.

Using function notation, we can define the Average Rate of Change of a function f from a to b as:

                                     rate(m) = \frac{f(b)-f(a)}{b-a}

The given function is  g(x) = 5(2)^{x},

Now calculating the average rate of change of function from x = 1 to x = 2.

                               m = \frac{g(b)-g(a)}{b-a}\\ m = \frac{g(2)-g(1)}{2-1}\\\\m=\frac{5(2)^{2}-5(2)^1}{2-1}\\ m=\frac{10}{1} \\m=10

Now, calculate the average rate of change of function from x = 3 to x = 4.

                                 m = \frac{g(b)-g(a)}{b-a}\\ m = \frac{g(4)-g(3)}{4-3}\\\\m=\frac{5(2)^{4}-5(2)^3}{4-3}\\ m=\frac{40}{1} \\m=40

The jump from m = 10 to m = 40 is "times 4".

So option (A) is correct.

Hence, The average rate of change of function g(x)=5(2)^{x} from x = 3 to x = 4 is 4 times that from x = 1 to x = 2.

To learn more about the average rate of change of function, visit:

brainly.com/question/24313700

#SPJ1  

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Plz help me I will mark u Brainiest
Reika [66]

Answer: 1- quadrant 1 or top right

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3-quadrant 3 or bottom left

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Wouldnt you divide ? so itll be 5.62 
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