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3 years ago

Y varies inversely with x, and k (the constant of variation) = 1.24. What is the value of y when x = 4.96?

Mathematics

1 answer:

V125BC [204]3 years ago

6 0

Answer:= y = 0.25 to the nearest hundredth.

Step-by-step explanation:

In inverse variation, both variables move in opposite directions. This means that as variable 1 increases, variable 2 reduces and as variable 1 reduces, variable 2 increases.

Y varies inversely with x.

So as y increases, x reduces and as y reduces, x increases.

We would proceed by introducing a constant of variation, k

y = k/x

From the information given,

The constant of variation, k = 1.24

The value if x = 4.96

To find the value of y

y = k/x = 1.24/4.96

= 0.25 to the nearest hundredth.

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3 years ago

Read 2 more answers

Fifty-five percent of the members of the junior varsity swim team wear glasses. Of the team memebers who do not wear glasses, 30

GarryVolchara [31]

the probability that a randomly chosen member of the JV swim team does not wear glasses and is in the 10th grade is 14%.

Given, the members of the junior varsity swim team wear glasses is 55%.

And the members of junior varsity swim team who do not wear glasses and in 10th grade is 30%.

Let the total no. of members be x.

So, the members of the junior varsity swim team wear glasses (55%),will be

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$x - 0.55 x = 0.45 x$ .

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$\frac{0.45x\times30}{100} =0.135x$

We know that the probability of an event E, P(E) will be,

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So, the probability for no. of members not wearing glasses and in 10th grade will be,

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Hence the nearest whole percent of probability is 14%.

For more details on probability follow the link:

brainly.com/question/795909

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3 years ago

There are 20 students in a math class. Thirty percent of the

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Answer:

Step-by-step explanation:

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3 years ago

What's the correct answer for this?

11Alexandr11 [23.1K]

$\bf \qquad \qquad \textit{inverse proportional variation}\\\\
\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad y=\cfrac{k}{x}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\$

$\bf \textit{\underline{N} is inversely proportional to \underline{A}}\qquad N=\cfrac{k}{A}
\\\\\\
\textit{we also know that }
\begin{cases}
A=3\\
N=16
\end{cases}\implies 16=\cfrac{k}{3}\implies 16\cdot 3=k
\\\\\\
48=k\qquad thus\qquad \boxed{N=\cfrac{48}{A}}\\\\
-------------------------------\\\\
\textit{if \underline{A} is 4, what is \underline{N}?}\qquad N=\cfrac{48}{4}$

4 0

3 years ago