You have this information about ΔABC, ΔFDE, and ΔGIH:
2 answers:
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The correct answer is shown in attached figure
To find the correct graph, we should study the continuity of the function
Check the continuity at x = -2
from the left ⇒⇒ f(-2) = 1/2 * -2 + 3 = 2
from the right ⇒⇒ f(-2) = 2
∴ The function is continuous at x = -2
Check the continuity at x = 3
from the left ⇒⇒ f(3) = 2
from the right ⇒⇒ f(3) = 2*3 - 3 = 3
∴ The function is jump discontinuous at x = 3
From the previous results the correct graph is the last as shown in attached graph.
To find the correct graph, we should study the continuity of the function
Check the continuity at x = -2
from the left ⇒⇒ f(-2) = 1/2 * -2 + 3 = 2
from the right ⇒⇒ f(-2) = 2
∴ The function is continuous at x = -2
Check the continuity at x = 3
from the left ⇒⇒ f(3) = 2
from the right ⇒⇒ f(3) = 2*3 - 3 = 3
∴ The function is jump discontinuous at x = 3
From the previous results the correct graph is the last as shown in attached graph.
Answer:
17
Step-by-step explanation:
Since angle KLJ~angle VWU are similar :
KL / WV = KJ/ UV
(25 / 20) = (4x - 23 / 2x + 2)
Cross multiply :
25(2x + 2) = 20(4x - 23)
50x + 50 = 80x - 460
50x - 80x = - 460 - 50
-30x = -510
x = 510 / 30
x = 17
