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Naddika [18.5K]
3 years ago
7

HELP ME NOW OR NO DINO NUUGETS​

Mathematics
2 answers:
OlgaM077 [116]3 years ago
8 0

Answer:

what do you want me to help you with cuz there's nothing attached??

Step-by-step explanation:

Hoochie [10]3 years ago
4 0
Could you attach the work? Thank you love!
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The correct answer is c
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Answer:

I think it's 18

Step-by-step explanation:

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Which addition property is demonstrated by this problem?<br><br> 23 + (4 + 3) = (23 + 4) + 3
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Answer;
Commutative Property

It is considered commutative when changing the order of the operands does not change the result.

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3 years ago
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3 years ago
Which expression is equivalent to...? Screenshots attached. Please help! Thank you.
Studentka2010 [4]

Answer:

4x^{3} y^{2} (\sqrt[3]{4 x y})

Step-by-step explanation:

Another complex expression, let's simplify it step by step...

We'll start by re-writing 256 as 4^4

\sqrt[3]{256 x^{10} y^{7} } = \sqrt[3]{4^{4} x^{10} y^{7} }

Then we'll extract the 4 from the cubic root.  We will then subtract 3 from the exponent (4) to get to a simple 4 inside, and a 4 outside.

\sqrt[3]{4^{4} x^{10} y^{7} } = 4 \sqrt[3]{4 x^{10} y^{7} }

Now, we have x^10, so if we divide the exponent by the root factor, we get 10/3 = 3 1/3, which means we will extract x^9 that will become x^3 outside and x will remain inside.

4 \sqrt[3]{4 x^{10} y^{7} } = 4x^{3} \sqrt[3]{4 x y^{7} }

For the y's we have y^7 inside the cubic root, that means the true exponent is y^(7/3)... so we can extract y^2 and 1 y will remain inside.

4x^{3} \sqrt[3]{4 x y^{7} } = 4x^{3} y^{2} \sqrt[3]{4 x y}

The answer is then:

4x^{3} y^{2} \sqrt[3]{4 x y} = 4x^{3} y^{2} (\sqrt[3]{4 x y})

4 0
3 years ago
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