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CaHeK987 [17]
3 years ago
9

Please Help. I will give brainlest to the person who answers this questions right

Mathematics
1 answer:
bija089 [108]3 years ago
3 0
By my calculations and understanding into this problem I have figured out the answer to this thing and it is very simple and easy enough to actually say it so I can type it out instead because I can’t say anything on this thing even though I’m doing a voice record and I don’t even know how my grandma is doing right now so I’m just blah bling around is it random words of mine but honestly I would love to explain and tell you the answer but I do not know how to type it out so I’m just going to say it like I just said two seconds ago but I didn’t really say it again I just typed it I don’t know I keep getting confused with that but anyways the answer is very easy
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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B10%7D%20%3D%20%20%5Cfrac%7B4%7D%7Ba-3%7D" id="TexFormula1" title=" \frac{2
Alexxandr [17]
Hello there!

Let's \ first \ rearrange \ the \ equation! \\ \\ (     2/10-(4/a-3)=0 ) \\ \\ we \ first \ simply \ simplify \ first \ \boxed{ \frac{4}{a} } \\ \\   \left[\begin{array}{ccc}\  \left[\begin{array}{ccc}\boxed{ \frac{2}{10}-( \frac{4}{a})-3)=0} \end{array}\right] \end{array}\right]  \\ \\ We \ then \ subtract \ its \ whole \ numbers. \\ \\ \boxed{3= \frac{3}{1} = \frac{3*a}{a} } \\ \\

\Longrightarrow   \left[\begin{array}{ccc}2/10-(4-3a)/a=\boxed{0}\end{array}\right]  \\ \\ we \ then \ simplify \ \boxed{1/5 \\ \\ 1/5-(4-3a)/a=0} \\ \\ \\ \boxed{\boxed{ \frac{a-((4-3a)*5}{5a} = \frac{16a-20}{5a} }} \\ \\  we \ then \ pull \ out \ some \ like \ terms . \\ \\   16a - 20  =   4 * (4a - 5) \\ \\  solve \  4   =  0 \ ; solve \ 4a-5 = 0 . \\ \\ &#10;&#10;\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow\Downarrow

\boxed{TAKE \ NOTICE} \\ \\ \\ \boxed{\boxed{ Add \  5  \ to \ both \ sides \ of  \ the \ equation : \   4a = 5 }} \\ \\ \\   \left[\begin{array}{ccc}  \left[\begin{array}{ccc}Divide  \ both \ sides \ of \ the \ equation \ by  \4: \\&#10;                     a = 5/4 = 1.250 \end{array}\right] \end{array}\right]  \\ \\ \\ \boxed{\boxed{Your \ correct \ answers}}... \\ \\ \\ \boxed{  a = 5/4 = 1.250}

I hope this helps you Cher! 
7 0
3 years ago
The number used to divide is the
irina1246 [14]
Hello there!

The answer is the divider.

Hope This Helps You!
Good Luck :)
6 0
3 years ago
Read 2 more answers
Consider the following equation. 9x2 − y2 = 6 (a) Find y' by implicit differentiation. y' = (b) Solve the equation explicitly fo
qaws [65]

Answer:

Step-by-step explanation:

Given is an equation in x and y as

9x^2 - y^2 = 6

We use implicit method to differentiate the above equation

18x-2yy'=0

y' = 9x/y

b) to solve the equation explicitly for y and differentiate to get y' in terms of x. y' = ±

We separate the variables as

yy' =9x\\\frac{y^2}{2} =\frac{9x^2}{2} +C\\y^2 =9x^2+2C

Take square root

y=\sqrt{9x^2+2C} \\y=-\sqrt{9x^2+2C}

6 0
3 years ago
Find the equation of the ellipse with the following properties.
zalisa [80]
Equation of an ellipse:

(x-h)²/a² + (y-k)²/b² = 1
Since it passes through the origin (0,0) , then h = k = 0 hence the equation:
(x-0)²/a² + (y-0)²/b² = 1
x²/a² + y²/b² = 1

2a = major axis = 2.|5| + |-5| = 10. then a = 5 and a² = 25
2b = minor axis = 2.|3| + |-3| = 6. then b = 3 and b² = 9

Then the final equation is:
x²/25 + y²/9 = 1

6 0
3 years ago
What is the answer to this problem above?
Ronch [10]

Answer:

Value of f (Parapedicular) = 7√6

Step-by-step explanation:

Given:

Given triangle is a right angle triangle

Value of base = 7√2

Angle made by base and hypotenuse = 60°

Find:

Value of f (Parapedicular)

Computation:

Using trigonometry application

Tanθ = Parapedicular / Base

Tan60 = Parapedicular / 7√2

√3 = Parapedicular / 7√2

Value of f (Parapedicular) = 7√2 x √3

Value of f (Parapedicular) = 7√6

4 0
3 years ago
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