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3 years ago

9

Please Help. I will give brainlest to the person who answers this questions right

1 answer:

bija089 [108]3 years ago

3 0

By my calculations and understanding into this problem I have figured out the answer to this thing and it is very simple and easy enough to actually say it so I can type it out instead because I can’t say anything on this thing even though I’m doing a voice record and I don’t even know how my grandma is doing right now so I’m just blah bling around is it random words of mine but honestly I would love to explain and tell you the answer but I do not know how to type it out so I’m just going to say it like I just said two seconds ago but I didn’t really say it again I just typed it I don’t know I keep getting confused with that but anyways the answer is very easy

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37040 divided by 3600

Alex

10.3(rounded to the nearest hundredth)
10.29(Rounded to the nearest tenth)
10.2888888889 real answer

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3 years ago

QUICK HELP!!!<br> How manny differences can you spot? <br> 8<br> 6<br> 7<br> 4<br> 3<br> 5

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i can only see 3

Step-by-step explanation:

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3 years ago

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Mr. Logan agrees to give you a loan of 25,000 to start your business, but charge you 7% interest. How much will you have to pay

Hitman42 [59]

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Step-by-step explanation:

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3 years ago

The sample space of a random experiment is {a, b, c, d, e} with probabilities 0.1, 0.1, 0.2, 0.4, and 0.2 respectively. Let A de

antoniya [11.8K]

Answer:

a) $P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4$

b) $P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8$

c) $P(A') = 1-P(A) =1-0.4=0.6$

d) $P(A \cup B) =0.4 +0.8-0.2 =1.0$

e) The intersection between the set A and B is the element c so then we have this:

$P(A \cap B) = P(c) =0.2$

Step-by-step explanation:

We have the following space provided:

$S= [a,b,c,d,e]$

With the following probabilities:

$P(a) =0.1, P(b)=0.1, P(c) =0.2, P(d)=0.4, P(e)=0.2$

And we define the following events:

A= [a,b,c], B=[c,d,e]

For this case we can find the individual probabilities for A and B like this:

$P(A) = 0.1+0.1+0.2 = 0.4$

$P(B) =0.2+0.4+0.2=0.8$

Determine:

a. P(A)

$P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4$

b. P(B)

$P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8$

c. P(A’)

From definition of complement we have this:

$P(A') = 1-P(A) =1-0.4=0.6$

d. P(AUB)

Using the total law of probability we got:

$P(A \cup B) =P(A) +P(B)-P(A \cap B)$

For this case $P(A \cap B) = P(c) =0.2$ , so if we replace we got:

$P(A \cup B) =0.4 +0.8-0.2 =1.0$

e. P(AnB)

The intersection between the set A and B is the element c so then we have this:

$P(A \cap B) = P(c) =0.2$

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3 years ago

2^m•2^n would be the same as___.

jarptica [38.1K]

${2}^{m + n}$

Step-by-step explanation:

$\huge {2}^{m} . {2}^{n} = {2}^{m + n}$

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3 years ago

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