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2 years ago

Please Help. I will give brainlest to the person who answers this questions right

Mathematics

1 answer:

bija089 [108]2 years ago

3 0

By my calculations and understanding into this problem I have figured out the answer to this thing and it is very simple and easy enough to actually say it so I can type it out instead because I can’t say anything on this thing even though I’m doing a voice record and I don’t even know how my grandma is doing right now so I’m just blah bling around is it random words of mine but honestly I would love to explain and tell you the answer but I do not know how to type it out so I’m just going to say it like I just said two seconds ago but I didn’t really say it again I just typed it I don’t know I keep getting confused with that but anyways the answer is very easy

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What is 10/8 written as a decimal?

ale4655 [162]

Answer:

1.25

Step-by-step explanation:

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3 years ago

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Which of the following is a solution of the system 2x + y = 9 and 3x + 5y = 19.

Nezavi [6.7K]

2x+y=9

3x+5y=19

I will do this problem in 2 ways. I.)Substitution II.)Elimination

Solution I.) Substitution

We can subtract 2x from both sides in the first equation.

y=9-2x

Now we can substitute the y in the second equation with 9-2x

3x+5(9-2x)=19

-7x+45=19

-7x=-26

x=26/7

y=9-2(26/7)=11/7

Solution II.)Elimination

We can multiply both side of first equation by 5 to get a 5y in both equations.

10x+5y=45

Now because both are positive 5y we just need to do simple subtraction of the 2 equation, each side respectively.

(10x+5y)-(3x+5y)=45-19

7x=26

x=26/7

2*26/7+y=9

y=11/7

Ultimately you get the same answer, both are viable methods, some problems are faster with one method but I recommend mastering both since they are very useful.

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2 years ago

Statements apply to the expression 8^3 ?check all that apply

hram777 [196]

Answer: So, 8%3 = 2

Step-by-step explanation:

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2 years ago

7, 14, and 21. What are the next three multiples?

Sergeu [11.5K]

7,14,21,28,35,42 ......................

6 0

3 years ago

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I need help with part b. I feel like there’s a catch, I want to do the first derivative test, however, I feel like there is a be

Sladkaya [172]

Answer:

The fifth degree Taylor polynomial of g(x) is increasing around x=-1

Step-by-step explanation:

Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

$P_5(x)=g(-1)+g'(-1)\,(x+1)+g"(-1)\, \frac{(x+1)^2}{2!} +g^{(3)}(-1)\, \frac{(x+1)^3}{3!} + g^{(4)}(-1)\, \frac{(x+1)^4}{4!} +g^{(5)}(-1)\, \frac{(x+1)^5}{5!}$

and when you do its derivative:

1) the constant term renders zero,

2) the following term (term of order 1, the linear term) renders: $g'(-1)\,(1)$ since the derivative of (x+1) is one,

3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero

Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: $g'(-1)= 7$ as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1

6 0

3 years ago