For this, we will be using the quadratic formula, which is $x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}$ , with a=x^2 coefficient, b=x coefficient, and c = constant. Our equation will look like this: $x=\frac{-6+/-\sqrt{6^2-4*(-2)*3}}{2*(-2)}$

Firstly, solve the multiplications and the exponents: $x=\frac{-6+/-\sqrt{36+24}}{-4}$

Next, do the addition: $x=\frac{-6+/-\sqrt{60}}{-4}$

Next, your equation will be split into two: $x=\frac{-6+\sqrt{60}}{-4},\frac{-6-\sqrt{60}}{-4}$ . Solve them separately, and your answer will be $x=-0.436,3.436$

5 0

3 years ago

If p varies directly with q, and p = 10 when q = 5, what is the value of p when q = 20

Inessa [10]

The value of p would be 40. This is because the ratio of p:q = 10:5. this could be simplify into p:q = 2:1. Applying the ratio p:20 = 2:1, P=40.

8 0

3 years ago