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patriot [66]
3 years ago
12

Suppose the radius of a circle is 2. What is its circumference?

Mathematics
1 answer:
Scilla [17]3 years ago
4 0

Answer:

12.57

Step-by-step explanation:

The formula to solve the circumference of a circle is:

2 x PI x R (radius)

=> 2 x PI x 2

=> 4 PI or 12.57

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vampirchik [111]
The answer is A I believe I may not be right but I think it is right sorry if I am wrong

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4 years ago
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a Gardener has 27 tulip bulbs 45 tomato plants 108 rose bushes and 162 her seedling to plant in the city garden he want each row
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Answer:

If you ment 126 herbs, then this is your answer

9 rows

Step-by-step explanation:

3 tulips + 5 tomato + 12 roses + 14 herbs

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4 years ago
-10x+45 find x when x =15
leonid [27]
Your answer is -105 pal
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3 years ago
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Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms oc
Anit [1.1K]

Answer:

a)\hat \sigma^2 =s^2 =30^2 = 900

b) 567.277 \leq \sigma^2 \leq 1690.224

Rounded to the nearest number would be:

567 \leq \sigma^2 \leq 1690

c) 23.818 \leq \sigma \leq 41.112

And rounded :

23.8 \leq \sigma \leq 41.1

Step-by-step explanation:

Data given and notation

s=30 represent the sample standard deviation

\bar x=290 represent the sample mean

n=20 the sample size

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

Part a

The best point of estimate for the population variance is the sample variance, so on this case:

\hat \sigma^2 =s^2 =30^2 = 900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,19)" "=CHISQ.INV(0.95,19)". so for this case the critical values are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma \leq \frac{(19)(30)^2}{10.117}

567.277 \leq \sigma^2 \leq 1690.224

Rounded to the nearest number would be:

567 \leq \sigma^2 \leq 1690

Part c

In order to find the confidence interval for the deviation we just need to take the square root for the interval of the variance, and we got:

23.818 \leq \sigma \leq 41.112

And rounded :

23.8 \leq \sigma \leq 41.1

7 0
3 years ago
Simplify the equation 5(3m-2)+4m
ipn [44]

Answer:

19m - 10

Step-by-step explanation:

Order of Operation: BPEMDAS

Step 1: Write out equation

5(3m - 2) + 4m

Step 2: Distribute parenthesis

15m - 10 + 4m

Step 3: Combine like terms

19m - 10

4 0
3 years ago
Read 2 more answers
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