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3 years ago

HELP FAST TRUE OR FALSE

Mathematics

1 answer:

jarptica [38.1K]3 years ago

5 0

It’s false because I got a big brain

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the mass of the sun is about 2 x 10^27 metric tons 0r 2 x 10^30 kilograms. how many kilograms are in one metric ton

Harlamova29_29 [7]

2x10^27 metric tons=2x10^30 KG
1 metric ton=(2x10^30)/(2x10^27) KG=10^3 KG = 1000 KG

7 0

4 years ago

Read 2 more answers

Algebra 2 math question

mafiozo [28]

Answer:

500 = 38t

Step-by-step explanation:

let x = minutes

f(x) = 500 + 38x

500 = 38t

graph

Hope this helped! Have a nice day! Plz mark as brainliest!!!

-XxDeathshotxX

6 0

3 years ago

Triangle ABC is the pre-image and triangle DFE is the image.

anzhelika [568]

Answer:

Scale factor = ½

Step-by-step explanation:

The original image is the preimage = ∆ACB

The new image is the image = ∆DFE

The scale of factor of dilation = image/preimage = DF/AC

DF = 6 cm (given)

AC = 12 cm (given)

Plug in the values into the equation to find the scale factor of dilation:

Scale factor = 6/12

Scale factor = ½

6 0

3 years ago

Please help ASAP!!!!!!!

kolezko [41]

Answer: the length of the base is 50 cm

Step-by-step explanation:

8 0

3 years ago

Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in s

Lerok [7]

Answer:

Q1 - D. f(x) = $x^4-9x^2-50x-150$

Q13 - A. ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24.

Q14 - A. $7x+6+4x^{2}$

Step-by-step explanation:

Question 1:

We know that rational roots always occurs in pairs. So, the zeros of the function will be 5, -3, -1+3i, -1-3i

So, the factored form is $(x-5)(x+3)(x+1-3i)(x+1+3i)=0$

i.e. $(x^2-2x-15)(x+1-3i)(x+1+3i)=0$

i.e. $(x^3-x^2-3ix^2-17x+6ix-15+45i)(x+1+3i)=0$

i.e. $x^4-9x^2-50x-150=0$

Hence, the polynomial function is $f(x)=x^4-9x^2-50x-150$ .

Question 13:

Rational Zeros Theorem states that 'If p(x) is a polynomial with integer coefficients and if $\frac{p}{q}$ is a zero of p(x) = 0. Then, p is a factor of the constant term of p(x) and q is a factor of the leading coefficient of p(x)'.

Let, $\frac{p}{q}$ is a zero of $x^3-7x^2+9x-24=0$ . Then, p is a factor of -24 and q is a factor of 1.

Thus, possible values of p = ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24 and q = ±1

This gives, possible values of $\frac{p}{q}$ are ±1, ±2, ±3, ±4, ±6, ±8, ±12, ±24.

Question 14:

We have, f(x) = 7x + 6 and g(x) = $4x^{2}$

Then, (f+g)(x) = f(x) + g(x) = 7x + 6 + $4x^{2}$

So, (f+g)(x) = $7x+6+4x^{2}$

6 0

4 years ago