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Dennis_Churaev [7]
3 years ago
10

Please help ASAP!!!!!!!

Mathematics
1 answer:
kolezko [41]3 years ago
8 0

Answer: the length of the base is 50 cm

Step-by-step explanation:

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Lilibeth has a collection of Marbles. Her collection is 3 3/4 times that of Maria’s collection
IceJOKER [234]

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1200

Step-by-step explanation:

15/4 × 320/1 = 4800/4

simplify

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Can someone help me solve this?
Virty [35]

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Her brothers pulse rate is 76.

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95% of 80 is 76. That only means that her brother's pulse rate must be 76 beats per minute.

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2 years ago
In the healthy handwashing survey conducted by Bradley Corporation, a study was found that 64% of adult Americans operate the fl
Hitman42 [59]

Answer:

<em>A) It fulfills the condition of binomial experiment</em>

<em>B) P (x=12) =0.1678</em>

<em>C)P ( x ≥16)= 0.1011</em>

<em>d) P (x>17) =0.0096 < 0.5</em>

Step-by-step explanation:

A. The binomial probability distribution has the following four properties

1. the outcomes of each trial maybe classified into success and failure.

2) the probability of success p remains constant for all trials.

3) the successive trials are all independent.

4) the experiment is repeated a fixed number of times ,n.

<em>These all conditions are fulfilled by the given question so it is a  binomial experiment. </em>

<em></em>

B) P (x=12) = 20C12 (0.64)^12 * (1-0.64)^8= 0.1678

C) P ( x ≥16) = P (x=16) + P (x=17) + P (x=18) + P (x=19)+ P (x=20)

where

P (x=16)= 20C16 (0.64)^16 * (1-0.64)^4= 0.0645

P (x=17)= 20C17 (0.64)^17 * (1-0.64)^3= 0.0270

P (x=18)= 20C18 (0.64)^18 * (1-0.64)^2= 0.0080

P (x=19)=20C19 (0.64)^10 * (1-0.64)^1= 0.0015

P (x=20)= 20C20 (0.64)^20 * (1-0.64)^0= 0.0001

so

P ( x ≥16)= 0.0645+ 0.0270 +0.0080+ 0.0015+0.0001= 0.1011

d) P (x>17)= P (x=17) + P (x=18) + P (x=19)+ P (x=20)

                    =0.0270 +0.0080+ 0.0015+0.0001

                         =0.0096

From this we see that the probability of  more than 17  people who flush public toilets with their foot is unusual because it is far away from the mean which is supposed to be somewhere 0.5 in a given distribution.

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Answer:

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