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Alexxx [7]
2 years ago
7

Find the volume of the cylinder A)1178ft3 B)7069ft3 C)4712ft3 D)3534ft3

Mathematics
1 answer:
Blizzard [7]2 years ago
7 0

Answer:

A) 1178

Step-by-step explanation:

height is 15

radius is 5

diameter is 10

π * 5^2 * 15= 1178

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Nine cyclists were each asked the distance in miles they biked last week.
Ivahew [28]

Answer:

Its A or the first option

Step-by-step explanation:

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4 0
2 years ago
Helppp fast (picture)
harkovskaia [24]
The answer to your question is the first option! Hope this helps. God bless
4 0
3 years ago
The Fahrenheit and Celsius scales are related by the equation F=9/5C+32. What temperature is equal to a body temperature of 98.6
____ [38]

\textbf{Substitute\ in\ the\ equation}

\displaystyle 98.6 = \frac{9C}{5} +32

\textbf{Solve\ for\ }C

\displaystyle 66.6 = \frac{9C}{5}

333=9C

\large C=\textbf{37 \textdegree C}

7 0
2 years ago
Find the volume of the square pyramid showing. round to the nearest 10th if necessary
solong [7]
The volume of a square pyramid is (1/3)(area of base)(height of pyramid).

Here the area of the base is (10 ft)^2 = 100 ft^2.

13 ft is the height of one of the triangular sides, but not the height of the pyramid.  To find the latter, draw another triangle whose upper vertex is connected to the middle of one of the four equal sides of the base by a diagonal of length 13 ft.  That "middle" is 5 units straight down from the upper vertex.  Thus, you have a triangle with known hypotenuse (13 ft) and known opposite side 5 feet (half of 10 ft).  What is the height of the pyramid?  
To find this, use the Pyth. Thm.:  (5 ft)^2 + y^2 = (13 ft)^2.  y = 12 ft.

Then the vol. of the pyramid is (1/3)(area of base)(height of pyramid) =
(1/3)(100 ft^2)(12 ft) = 400 ft^3 (answer)
5 0
3 years ago
I own a large truck, and my neighbor owns four small trucks that are all identical. My truck can carry a load of at least $600$
erastova [34]

Answer:

  there is no greatest load

Step-by-step explanation:

Let x and y represent the load capacities of my truck and my neighbor's truck, respectively. We are given two relations:

  x ≥ y +600 . . . . . my truck can carry at least 600 pounds more

  x ≤ (1/3)(4y) . . . . . my truck carries no more than all 4 of hers

Combining these two inequalities, we have ...

  4/3y ≥ x ≥ y +600

  1/3y ≥ 600 . . . . . . . subtract y

  y ≥ 1800 . . . . . . . . multiply by 3

My truck's capacity is greater than 1800 +600 = 2400 pounds. This is a lower limit. The question asks for an <em>upper limit</em>. The given conditions do not place any upper limit on truck capacity.

4 0
2 years ago
Read 2 more answers
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