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Vikentia [17]
3 years ago
9

In a school with 615 students, 18 classes are formed. If the classes are equal in size, and far as possible, how many classes ar

e larger than the others?
a. 1
b.0
c. 2
d. 4
e. 3
Mathematics
2 answers:
VashaNatasha [74]3 years ago
7 0
C because if you divide 615 by 18 it would be 34.1666667 
german3 years ago
6 0
The answer is c or 2!
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Let f(x) = 4x – 2 and g(x) = x + 1. Find the following function value.<br> (f - g)(-3)
Nataly [62]

Answer:

(f - g)(3) = 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

  • Function Notation

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 4x - 2

g(x) = x + 1

<u>Step 2: Find</u>

<em>Find (f - g)(x)</em>

  1. Substitute:                         (f - g)(x) = 4x - 2 - (x + 1)
  2. Distribute -1:                      (f - g)(x) = 4x - 2 - x - 1
  3. Combine like terms:         (f - g)(x) = 3x - 3

<em>Find (f - g)(3)</em>

  1. Substitute:                         (f - g)(3) = 3(3) - 3
  2. Multiply:                             (f - g)(3) = 9 - 3
  3. Subtract:                            (f - g)(3) = 6
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2 years ago
F(t) = 2t - 3 evaluate the function
Olenka [21]

Answer:

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Step-by-step explanation:

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3 years ago
Write a rule for the nth term of the sequence. Then find a20. Assume the first termis a₁. 86, 79, 72, 65…
hodyreva [135]

Answer:

an = a(n-1) - 7

Step-by-step explanation:

the second term is smaller than the first term 7.

a20 = a19 - 7

a19 = a18 - 7

=> a20 = (a18 - 7) - 7

Then you can accumalate until a1

-> a20 = a1 - 19*7 = 86 - 19*7 = -47

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2 years ago
A population of rabbits in a lab, p(x), can be modeled by the function p(x) = 20(1.014)x , where x represents the number of days
Nitella [24]

Answer:

20 = initial population of the rabbits

1.014 = growth rate of the rabbits

the average rate of change from day 50 to day 100 is 0.8

Step-by-step explanation:

A population of rabbits in a lab, p(x), can be modeled by the function

p(x) = 20(1.014)^x

This model is exponential. Where 20 = initial population of the rabbits

1.014 = growth rate of the rabbits with 1.4% increase rate of the rabbits

To find the average rate of change from day 50 to day 100,

find the population p(50) and p(100). Subtract them and divide by 100 - 50 = 50. 

p(50) = 20(1.014)50 = 40.08... 

p(100) = 20(1.014)100 = 80.32... 

(80.32 - 40.08) / (100 - 50) = 40.24/50 = 0.8048. which is approximately 0.8 to the nearest tenth. 

The rate of change is 0.8. 

7 0
3 years ago
Help me plss, number 2.​
Gnesinka [82]

Answer:

At (-2,0) gradient is -4 ; At (2,0) gradient is 4

Step-by-step explanation:

For this problem, we simply need to take the derivative of the function and evaluate when y = 0 (when crossing the x-axis).

y = x^2 - 4

y' = 2x

The function y = x^2 - 4 cross the x-axis when:

y = x^2 - 4

0 = x^2 - 4

4 = x^2

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Hence, this curve crosses the x-axis twice, once at (-2,0) and again at (2,0).

The gradient at these points are as follows:

y' = 2(-2) = -4

y' = 2(2) = 4

Cheers.

3 0
3 years ago
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