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Alex_Xolod [135]
3 years ago
10

Solve for x. WRITE AN EQUATION AND SHOW YOUR WORK

Mathematics
1 answer:
PolarNik [594]3 years ago
4 0

Answer:

9) x = 9

10) x = - 8

11) x = 7

Step-by-step explanation:

9)

(180 - 15x + 4) + 7x + 1 + 67 = 180

180 - 15x + 4 + 7x + 1 + 67 = 180

-15x + 4 + 7x + 1 + 67 = 0

-8x + 72 = 0

72 = 8x

x = 9

10)

100 = x + 108

100 - 108 = x

x = -8

11)

10x - 1 + 17x - 8 = 180

27x - 9 = 180

27x = 189

x = 7

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Find each of the following for ​
KATRIN_1 [288]
<h2>Answer:</h2>

(a)

          f(x+ h)=8x+8h+3  

(b)

            f(x+ h)-f(x)=8h          

(c)

             \dfrac{f(x+ h)-f(x)}{h}=8

<h2>Step-by-step explanation:</h2>

We are given a function f(x) as :

              f(x)=8x+3

(a)

           f(x+ h)

We will substitute (x+h) in place of x in the function f(x) as follows:

f(x+h)=8(x+h)+3\\\\i.e.\\\\f(x+h)=8x+8h+3

(b)

       f(x+ h)-f(x)              

Now on subtracting the f(x+h) obtained in part (a) with the function f(x) we have:

f(x+h)-f(x)=8x+8h+3-(8x+3)\\\\i.e.\\\\f(x+h)-f(x)=8x+8h+3-8x-3\\\\i.e.\\\\f(x+h)-f(x)=8h

(c)

           \dfrac{f(x+ h)-f(x)}{h}            

In this part we will divide the numerator expression which is obtained in part (b) by h to get:

           \dfrac{f(x+ h)-f(x)}{h}=\dfrac{8h}{h}\\\\i.e.\\\\\dfrac{f(x+h)-f(x)}{h}=8    

5 0
3 years ago
A square window has an area of 196
creativ13 [48]

Answer:

14 feet

Step-by-step explanation:

s2 = 196

3 0
3 years ago
I don’t understand Please help!
AlekseyPX

Answer:

The answer is water.........

5 0
3 years ago
I need help for this, thanks
gulaghasi [49]

(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.

---------------------------------------------------------------------------------------

(b) The following functions are positive in quadrant III:

tangent, cotangent

The following functions are negative in quadrant III

cosine, sine, secant, cosecant

A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.

5 0
3 years ago
what is the volume of a triangular prism that is 75 centimeters long and that has a base with an area of 30 square centimeters
pychu [463]
75 * 30= 2250 that's how u get the answer
3 0
3 years ago
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