This is in the fourth quadrant where the cosine is positive
By pythagoras the hypotenuse is 5
so the cosine is 3/5 B
<u>Given</u><u>:</u>
- mass of cat ( m ) = 10 kg
- Acceleration ( a ) = 10 m/s²
<u>To</u><u> </u><u>find</u><u> </u><u>out</u><u>:</u><u> </u>
If it runs into a wall what force will be exerted by the cat?
<u>Formula</u><u> </u><u>used</u><u>:</u>
Force = mass × acceleration
<u>Solution</u><u>:</u>
Force = mass × acceleration
Now, Putting these values of m and a in the above equation.
we get:
F = 10 × 10
= 100 N
Thus, the force will be exerted by the cat is 100 N.
Total = Principal * (1 + rate)^years
Total = 650 * (1.08)^14
<span>Total = 1,909.1</span>8
Answer:
You can spend 4 days in Los Angeles and 3 days in San Francisco.
Step-by-step explanation:
From the information given, you can write the following equations:
x+y=7 (1)
275x+400y=2,300 (2), where:
x is the number of days to visit Los Angeles
y is the number of days to visit San Francisco
First, you can solve for x in (1):
x=7-y (3)
Now, you can replace (3) in (2):
275(7-y)+400y=2,300
1,925-275y+400y=2,300
125y=2,300-1,925
125y=375
y=375/125
y=3
Finally, you can replace the value of y in (3) to find x:
x=7-3
y=4
According to this, the answer is that you can spend 4 days in Los Angeles and 3 days in San Francisco.
I am assuming 33 is B^(2/3) times B^(1/2)
See the following image