Can someone help with this

Mathematics

1 answer:

Alchen [17]4 years ago

7 0

1. 2 ft 9 in
2. 1 ft 1 in
3. 8 ft 7 in
4. 6 ft 5 in
5. 8 ft. 1 in
6. 4 ft 4 in
7. 10 ft 2 in

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g You plan to construct a confidence interval for the mean μ μ of a Normal population with known standard deviation σ . σ. Which

muminat

Answer:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The margin of error is given by:

$ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

And we can reduce this margin of error with:

Increasing the sample size

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma$ represent the population standard deviation

n represent the sample size

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The margin of error is given by:

[tex] ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

And we can reduce this margin of error with:

Increasing the sample size

5 0

4 years ago

Ben wants to try a new honey-glazed salmon recipe. He starts with 1 2/3 cups of honey. He uses 1/5 of it to make the glaze. How

GalinKa [24]

Answer:

1 1/3

Step-by-step explanation:

Firstly, 1 2/3 is converted into an improper fraction being 5/3. Next, 1/5 of 5/3 is one portion of 5 equal portions. You can split 5/3 into five equal portions of 1/3. Therefore, 1/3 cup of honey was used to make the honey glaze. Lastly, that is subtracted from the 1 2/3 to end up with 1 1/3.

8 0

3 years ago

Number 7 what would all answers be

Over [174]

So... notice the picture below, that's P(x)

so $\bf \qquad \qquad \textit{vertex of a parabola}\\ \quad \\
y = {{ a}}x^2{{ +b}}x{{ +c}}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)$

so.. when the quantity is $\bf -\cfrac{{{ b}}}{2{{ a}}}$ , is when the profit $\bf {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}$ is the highest

after that, as you can see from the graph, it goes back down