9514 1404 393
Answer:
x = 3
Step-by-step explanation:
Tangents to a circle from the same point are the same length.
43 -2x = 12x +1
42 = 14x . . . . . . . add 2x-1
3 = x . . . . . . . divide by 14
Answer: 7,8,9
Step-by-step explanation:
Let the numbers be a, a+1 and a+2. Therefore, based on the question, this will be:
= (a + 1)(a + 2) = 72
a² + 2a + a + 2 = 72
a² + 3a + 2 - 72 = a
a² + 3a - 70 = 0
a² + 10a - 7a - 70 = 0
a(a + 10) - 7(a + 10)
a - 7 = 0
a = 7
Since a = 7
a + 1 = 7+1 = 8
a + 2 = 7+2 = 9
The numbers are 7,8 and 9
The given expression is ![\frac{\sqrt{2}}{\sqrt[3]{2}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%20%20%20%20)
This can be simplified using the radical properties as below
![\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}} \\\\](https://tex.z-dn.net/?f=%20%5C%5C%5C%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D%5Cfrac%7B2%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B2%5E%5Cfrac%7B1%7D%7B3%7D%7D%20%5C%5C%5C%5C%20%20%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D%5Cfrac%7B2%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B2%5E%5Cfrac%7B1%7D%7B3%7D%7D%20%5C%5C%5C%5C%20)
Now using exponent properties we can write
![\\\ \frac{\sqrt{2}}{\sqrt[3]{2}}=\frac{2^{\frac{1}{2}}}{2^\frac{1}{3}}=2^{\frac{1}{2}-\frac{1}{3}} \\\\\frac{\sqrt{2}}{\sqrt[3]{2}}=2^{\frac{3-2}{6}}=2^\frac{1}{6}\\\\= \sqrt[6]{2}\\](https://tex.z-dn.net/?f=%20%5C%5C%5C%20%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D%5Cfrac%7B2%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B2%5E%5Cfrac%7B1%7D%7B3%7D%7D%3D2%5E%7B%5Cfrac%7B1%7D%7B2%7D-%5Cfrac%7B1%7D%7B3%7D%7D%20%5C%5C%5C%5C%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%5B3%5D%7B2%7D%7D%3D2%5E%7B%5Cfrac%7B3-2%7D%7B6%7D%7D%3D2%5E%5Cfrac%7B1%7D%7B6%7D%5C%5C%5C%5C%3D%20%5Csqrt%5B6%5D%7B2%7D%5C%5C%20)
it could be 2.2 because every 5 you get 2 so it would be 10 and 4 so when y=6 then x should be 2.2.
We first calculate Emily's rate by dividing the distance from her home to the post office by the time it took her to travel that distance. From 8:25 to 8:29 (and 30 seconds), there are exactly 4.5 minutes. Thus, the rate is equal to,
r = (0.75 miles) / (4.5 minutes) = 1/6 miles/min
Then, we divide the given distance from her home to school by the calculate rate to determine the total number of minutes it will take her to travel to school.
t = (3.42 miles)/(1/6 miles/min) = 20.52 minutes
Adding this to 8:25 will give us an answer of 8:45 and 31.2 seconds. She will not be late.
