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bagirrra123 [75]
3 years ago
6

What is the missing term of the arithmetic sequence? 6, ______, 30

Mathematics
1 answer:
Andrei [34K]3 years ago
3 0

Let k = the constant amount added to the sequence since this is an arithmetic sequence

       x = missing number

You have to formulate an equation based on the sequence:

6 + k = x or k = x – 6

x + k = 30

Substitute the value of k to the second formula:

x + x – 6 = 30

2x = 36

x = 18

Therefore, the missing number is 18.

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In most microcomputers the addresses of memory locations are specified in hexadecimal. These addresses are sequential numbers th
iren [92.7K]

Considering that the addresses of memory locations are specified in hexadecimal.

a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ )  = 65536 memory locations

b) The range of hex addresses in a microcomputer with 4096 memory locations is ;  4095

<u>applying the given data </u>:

a) first step : convert FFFF₁₆ to decimal           ( note F₁₆ = 15 decimal )

( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )

= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )

=  61440 + 3840 + 240 + 15 = 65535

∴ the memory locations from  0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations

b) The range of hex addresses with a memory location of 4096

= 0000₁₆ to FFFF₁₆ =  0 to 4096

∴ the range = 4095

Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.

Learn more : brainly.com/question/18993173

6 0
3 years ago
I need help!! I'll report if wrong ​
ss7ja [257]

Answer:

23

Step-by-step explanation:

2+2+3+4+5+6 = 23

3 0
3 years ago
What is the degree <br> A. 2<br> B. 3<br> C. 6<br> D. 8
sasho [114]
6 hope i could help good luck
4 0
3 years ago
In ΔOPQ, o = 9.2 cm, p = 2.4 cm and ∠Q=37°. Find the length of q, to the nearest 10th of a centimeter.
storchak [24]

The length of q, to the nearest 10th of a centimeter is 7.6 cm.

Given in question,

In ΔOPQ,

o = 9.2 cm

p = 2.4 cm

∠Q = 37°

Cosine formula ⇒ cos θ = \frac{o^{2}+p^{2}-q^{2}  }{2op}

Putting the values in equation,

       cos 37 = \frac{(9.2)^{2}+(2.4)^{2}-q^{2}  }{2*9.2*2.4}

         0.799 = \frac{84.64 + 5.76-q^{2} }{44.16}

0.799*44.16 = 90.4 - q^{2}

         32.28 = 90.4 - q^{2}

                q^{2} = 90.4 - 32.28

                q^{2} = 58.12

                 q = \sqrt{58.12}

                 q = 7.63

q = 7.6 cm (to nearest 10th)

Hence, length of q is 7.6 cm.

Learn more about length on:

brainly.com/question/8552546

#SPJ1

3 0
1 year ago
A resident of Bayport claims to the City Council that the proportion of Westside residents
Kazeer [188]

Answer:

The test statistics is  z =  -1.56  

The p-value is   p-value =  0.05938

Step-by-step explanation:

From the question we are told  

   The West side sample  size is n_1  =  578

    The  number of residents on the West side with income below poverty level is k  = 76

    The East side sample size  n_2=688

  The  number of residents on the East side with income below poverty level is u  = 112

   The null hypothesis is  H_o  :  p_1 = p_2

    The alternative hypothesis is  H_a :  p_1 <  p_2

Generally the sample proportion of  West side is  

     \^{p} _1 = \frac{k}{n_1}

=>   \^{p} _1 = \frac{76}{578}

=>   \^{p} _1 =  0.1315

Generally the sample proportion of  West side is  

     \^{p} _2 = \frac{u}{n_2}

=>   \^{p} _2 = \frac{112}{688}

=>   \^{p} _2 =  0.1628

 Generally the pooled sample proportion is mathematically represented as

    p = \frac{k + u}{ n_1 + n_2 }

=>  p = \frac{76 + 112}{ 578 + 688 }

=>  p =0.1485

Generally the test statistics is mathematically represented as

z = \frac{\^ {p}_1 - \^{p}_2}{\sqrt{p(1- p) [\frac{1}{n_1 } + \frac{1}{n_2}  ]}  }

=> z = \frac{ 0.1315  - 0.1628 }{\sqrt{0.1485(1-0.1485) [\frac{1}{578} + \frac{1}{688}  ]}  }  

=> z =  -1.56  

Generally the p-value  is mathematically represented as

          p-value =  P(z <  -1.56 )

From z-table  

         P(z <  -1.56 ) =  0.05938

So

     p-value =  0.05938

3 0
3 years ago
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