5,435,977 5,432,177 5,447,113 in number sentence

2 answers:

6 0

1. five million four hundred thirty-five thousand nune hundred seventy-seven
2. five million four hundred thirty-two thousand one hundred seventy-seven
3. five million four hundred fourty-seven thousand one hundred thirteen

otez555 [7]3 years ago

5 0

Five million- four hundred and thirty two thousand- one hundred and seventy seven
Five million - four hundred and thirty five thousand - nine hundred and seventy seven
Five million - four hundred and forty seven thousand - one hundred and thirteen

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What’s the area and perimeter?

Angelina_Jolie [31]

Answer:

•12

Step-by-step explanation:

fInd Little bit at end by pythogotous and find are of shaded the find areo of non shaded and take away with shaded triangle

4 0

2 years ago

Could someone help me, please?

k0ka [10]

We can rewrite the expression under the radical as

$\dfrac{81}{16}a^8b^{12}c^{16}=\left(\dfrac32a^2b^3c^4\right)^4$

then taking the fourth root, we get

$\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|$

Why the absolute value? It's for the same reason that

$\sqrt{x^2}=|x|$

since both $(-x)^2$ and $x^2$ return the same number $x^2$ , and $|x|$ captures both possibilities. From here, we have

The absolute values disappear on all but the $b$ term because all of $\dfrac32$ , $a^2$ and $c^4$ are positive, while $b^3$ could potentially be negative. So we end up with

$\dfrac32a^2\left|b^3\right|c^4=\dfrac32a^2|b|^3c^4$

3 0

3 years ago

Can someone please answer. There is one problem. There's a picture. Thank you!

allochka39001 [22]

$\dfrac{60^o}{360^o}=\dfrac{1}{6}\\\\A_O=\pi\cdot4^2=16\pi\\\\Area\ of\ the\ shaded\ sector:\\\\A=\dfrac{1}{6}\cdot16\pi=\dfrac{8}{3}\pi\approx\dfrac{8}{3}\cdot3.14\approx8.4\\\\Answer:\boxed{8.4}$