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3 years ago

A stick is 6 m long. A rope is 2 times as long as the stick.

Mathematics

1 answer:

weeeeeb [17]3 years ago

4 0

Answer:

Step-by-step explanation:

wouldn't it be 12 meters? is this isn't what you need ill figure it out and edit this

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Help, please I just can't.

IceJOKER [234]

Thousandths should be 3

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4 years ago

Solve each equation (Isolating first)

Dvinal [7]

$3 \times {( \frac{1}{8} )}^{2x} = 12 \\ \Leftrightarrow {( \frac{1}{8} )}^{2x} = 4 \\ \Leftrightarrow {( {2}^{ - 3}) }^{2x} = {2}^{2} \\ \Leftrightarrow {2}^{ - 6x} = {2}^{2} \\ \Leftrightarrow - 6x = 2 \\ \Leftrightarrow x = - \frac{1}{3} \\ \\ 2 {\sqrt[3]{5}}^{4x} = 50 \\ \Leftrightarrow { \sqrt[3]{5} }^{4x} = 25 \\ \Leftrightarrow {5}^{ \frac{4x}{3} } = {5}^{2} \\ \Leftrightarrow \frac{4x}{3} = 2 \\ \Leftrightarrow 4x = 6 \\ \Leftrightarrow x = \frac{3}{2}$

7 0

3 years ago

Read 2 more answers

A survey of 1282 student loan borrowers found that 440 had loans totaling more than $20,000 for their undergraduate education. G

Xelga [282]

Answer:

The 98% confidence interval of the proportion = (0.312, 0.374)

Step-by-step explanation:

(Give answers accurate to 3 decimal places.)

The formula for Confidence Interval of Proportion is given as:

p ± z × √p(1 - p)/n

Where p = Proportion = x/n

x = 440

n = 1282

p = 440/1282 = 0.34321372854

Approximately = 0.343

z = z-score of 98 % confidence interval

= 2.326

Confidence Interval =

= 0.343 ± 2.326 × √0.343(1 - 0.343)/1282

= 0.343 ± 2.326 × √0.225351/1282

= 0.343 ± 2.326 × √0.00017578081

= 0.343 ± 2.326 × 0.01325823555

= 0.343 ± 0.03083865589

0.343 - 0.03083865589

= 0.31216134411

Approximately = 0.312

0.343 + 0.03083865589

= 0.37383865589

Approximately to = 0.374

Therefore, the 98% confidence interval of the proportion = (0.312, 0.374)

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3 years ago

A scientist has discovered an organism that replicates at a rate of five per hour and lives for one week. Each replicated organi

bezimeni [28]

A)2,801

write an equation for the translation of y= [x]. 16.5 units

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4 years ago

Find the value of :x^2+2xy+y^2-3x-3y-1<br> have: x^2-y=y^2-x (x<img src="https://tex.z-dn.net/?f=%5Cneq" id="TexFormula1" title=

lidiya [134]

Answer: The answer is x^2+2xy+2y^2–3x–3y–1

Step-by-step explanation: Move 2 to the left of y^2.

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3 years ago