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3 years ago

What is the relationship that exist between two quantities in unit rate

2 answers:

7 0

Answer: If the relationship between two quantities is a proportional relationship, this relationship can be represented by the graph of a straight line through the origin with a slope equal to the unit rate.

Step-by-step explanation:

Molodets [167]3 years ago

6 0

If the relationship between two quantities is a proportional relationship, this relationship can be represented by the graph of a straight line through the origin with a slope equal to the unit rate.

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Combine like terms 9-5=9x-6x

4vir4ik [10]

Answer:

4 = 3x

Step-by-step explanation:

9-5=9x-6x

Combine like terms

4 = 3x

We can solve for x

Divide by 3

4/3 = 3x/3

4/3 =x

7 0

3 years ago

If W(-10, 4), X(-3, -1), and Y(-5, 11) classify ΔWXY by its sides. Show all work to justify your answer.

solniwko [45]

Given:

The vertices of ΔWXY are W(-10, 4), X(-3, -1), and Y(-5, 11).

To find:

Which type of triangle is ΔWXY by its sides.

Solution:

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$WX=\sqrt{(-3-(-10))^2+(-1-4)^2}$

$WX=\sqrt{(-3+10)^2+(-5)^2}$

$WX=\sqrt{(7)^2+(-5)^2}$

$WX=\sqrt49+25}$

$WX=\sqrt{74}$

Similarly,

$XY=\sqrt{\left(-5-\left(-3\right)\right)^2+\left(11-\left(-1\right)\right)^2}=2\sqrt{37}$

$WY=\sqrt{\left(-5-\left(-10\right)\right)^2+\left(11-4\right)^2}=\sqrt{74}$

Now,

$WX=WY$

So, triangle is an isosceles triangles.

and,

$WX^2+WY^2=(\sqrt{74})^2+(\sqrt{74})^2$

$WX^2+WY^2=74+74$

$WX^2+WY^2=148$

$WX^2+WY^2=(2\sqrt{37})^2$

$WX^2+WY^2=WY^2$

So, triangle is right angled triangle.

Therefore, the ΔWXY is an isosceles right angle triangle.

3 0

2 years ago

F(x) = x^2-3<br> What is the average rate of change on the interval [-5, 2] ?

Mumz [18]

Answer:

$(-3)$ .

Step-by-step explanation:

Over this interval, the change in the value of this function is:

$f(-5) - f(2) = 22 - 1 = 21$ .

The corresponding change in the value of $x$ :

$(-5) - 2 = -7$ .

The average rate of change of function $f$ over this interval is equal to the change in the function value divided by the corresponding change in $x$ :

$\begin{aligned}& (\text{average rate of change}) \\ =\; & \frac{(\text{change in function value})}{(\text{change in $x$})} \\ =\; & \frac{f(-5) - f(2)}{(-5) - 2} \\ =\; & \frac{22 - 1}{-7} \\ =\; & \frac{21}{-7} \\ =\; & -3\end{aligned}$ .

Thus, the average rate of change of $f(x) = x^{2} - 3$ over the interval $[-5,\, 2]$ would be $(-3)$ .

7 0

2 years ago

PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ HELPPPPPPPPPPPPPPPP

Sergeu [11.5K]

Answer:

2. y=9x

3. 180*9 = 1620

Step-by-step explanation:

2. y = mx+b, so find the slop efirst

lacampanella avatar

so take the first two points you got

lacampanella avatar

(2,18) and (5,45),

lacampanella avatar

(45-18)/(5-2) = 9

lacampanella avatar

then use (2,18)

lacampanella avatar

18= 9*2+b

lacampanella avatar

so b=0

3. y = 9x

x= 180. y = 9*180 = 1620

4 0

2 years ago

Round 9.88930605114 to the nearest ten-thousand

vlabodo [156]

Answer:

It is 9.8893

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is the relationship that exist between two quantities in unit rate​

What is the relationship that exist between two quantities in unit rate