2 years ago

Can someone help me

Mathematics

1 answer:

neonofarm [45]2 years ago

7 0

It is the second one

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How many solutions exist for the given equation? StartFraction one-half left-parenthesis x plus 12 right-parenthesis equals 4 x

Firlakuza [10]

Answer:

One solution x = 2

Step-by-step explanation:

Given the equation:

$\dfrac{1}{2}(x+12)=4x-1$

Multiply this equation by 2:

$2\cdot \dfrac{1}{2}(x+12)=2\cdot (4x-1)\\ \\x+12=2(4x-1)$

Use distributive property:

$x+12=8x-2$

Combine the like terms:

$x+12=8x-2\\ \\x+12-12=8x-2-12\\ \\x=8x-14\\ \\x-8x=8x-14-8x\\ \\-7x=-14\\ \\7x=14\\ \\x=2$

Thus, this equation has one solution x = 2

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3 years ago

Can someone help me​

Can someone help me