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mash [69]
3 years ago
13

A larger number is double the sum of 3 and a Shanel num

Mathematics
1 answer:
dmitriy555 [2]3 years ago
5 0

Answer:

y = 22; x = 8

y > x

Step-by-step explanation:

A larger number is double the sum of 3 and a smaller number. The larger number is 2 less than 3 times the smaller number. If y represents the larger number and x represents the smaller number, which equations model the situation? Check all that apply.

Let

Smaller Number = x

Larger number = y

larger number is double the sum of 3 and a Smaller number

Sum of 3 and a smaller number = 3 + x

y = 2(3 + x)

y = 6 + 2x (1)

Also

y = 3x - 2 (2)

Equate the equation of the larger number

6 + 2x = 3x - 2

6 + 2 = 3x - 2x

8 = x

x = 8

Substitute x = 8 into (1) to find y

y = 6 + 2x (1)

y = 6 + 2(8)

= 6 + 16

= 22

y = 22

y = 22; x = 8

Therefore,

y > x

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Write in point-slope form an equation of the line that passes through the point (6,−1) with slope −13.
denis-greek [22]

Answer:

y+1=-13(x-6)

Step-by-step explanation:

Point-slope form is denoted by: y-y_1=m(x-x_1), where (x_1,y_1) is the point and m is the slope.

Here, we know that our point is (6, -1) and the slope is -13. That means that x_1=6, y_1=-1, and m = -13. So plug these in:

y-y_1=m(x-x_1)

y+1=-13(x-6)

And, that's the answer: y+1=-13(x-6).

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4 years ago
For the function, find all critical numbers and then use the second-derivative test to determine whether the function has a rela
Serhud [2]

Answer:

relative maximum: x = 1

relative minimum: x = 7

Step-by-step explanation:

Critical points:

Values of x for which f'(x) = 0.

Second derivative test:

For a critical point, if f''(x) > 0, the critical point is a relative minimum.

Otherwise, if f''(x) < 0, the critical point is a relative maximum.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

f(x) = x^{3} - 12x^{2} + 21x - 8

Finding the critical points:

f'(x) = 3x^{2} - 24x + 21

3x^{2} - 24x + 21 = 0

Simplifying by 3

x^{2} - 8x + 7 = 0

So a = 1, b = -8, c = 7

\bigtriangleup = (-8)^{2} - 4*1*7 = 36

x_{1} = \frac{-(-8) + \sqrt{36}}{2} = 7

x_{2} = \frac{-(-8) - \sqrt{36}}{2} = 1

Second derivative test:

The critical points are x = 1 and x = 7.

The second derivative is:

f''(x) = 6x - 24

f''(1) = 6*1 - 24 = -18

Since f''(1) < 0, at x = 1 there is a relative maximum.

f''(7) = 6*7 - 24 = 18

Since f''(x) > 0, at x = 7 there is a relative minumum.

8 0
3 years ago
Using the table below, what is Esmeralda's take-home pay?
lina2011 [118]

Answer:

THE ANSWER IS $40,260

Step-by-step explanation:

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6 0
4 years ago
What is the factored form of X3-1?
jenyasd209 [6]
The third one, or C!
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3 years ago
A sales agent makes 40 calls a day. About 15% he calls result in a sale. How many days
Tems11 [23]

Answer: 20 days

Step-by-step explanation:

Since the sale agent makes 40 calls a day and about 15% he calls result in a sale. This means the number of sales will be:

= 15% × 40

= 0.15 × 40

= 6

6 sales out of every 40 calls per day.

The number of calls to make 120 sales will be:

= 15% of x = 120

0.15 × x = 120

0.15x = 120

x = 120/0.15

x = 800 calls

Since he needs 800 calls and he makes 40 calls per day, the number of days needed will be:

= 800/40

= 20 days

6 0
3 years ago
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