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3 years ago

Help please i am struggling.

Mathematics

1 answer:

Mama L [17]3 years ago

6 0

Answer:

what Netflix show were you watching?

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Rectangle JKLM with vertices J(-3,2), K(3,5), L(4,3), M(-2,0)<br> translation please

Wewaii [24]

Answer:

NOT! (10, 1)

Step-by-step explanation:

3 0

3 years ago

Solve the initial value problems.

slavikrds [6]

Both equations are linear, so I'll use the integrating factor method.

The first ODE

$xy' + (x+1)y = 0 \implies y' + \dfrac{x+1}x y = 0$

has integrating factor

$\exp\left(\displaystyle \int\frac{x+1}x \, dx\right) =\exp\left(x+\ln(x)\right) = xe^x$

In the original equation, multiply both sides by eˣ :

$xe^x y' + (x+1) e^x y = 0$

Observe that

d/dx [xeˣ] = eˣ + xeˣ = (x + 1) eˣ

so that the left side is the derivative of a product, namely

$\left(xe^xy\right)' = 0$

Integrate both sides with respect to x :

$\displaystyle \int \left(xe^xy\right)' \, dx = \int 0 \, dx$

$xe^xy = C$

Solve for y :

$y = \dfrac{C}{xe^x}$

Use the given initial condition to solve for C. When x = 1, y = 2, so

$2 = \dfrac{C}{1\cdot e^1} \implies C = 2e$

Then the particular solution is

$\boxed{y = \dfrac{2e}{xe^x} = \dfrac{2e^{1-x}}x}$

The second ODE

$(1+x^2)y' - 2xy = 0 \implies y' - \dfrac{2x}{1+x^2} y = 0$

has integrating factor

$\exp\left(\displaystyle \int -\frac{2x}{1+x^2} \, dx\right) = \exp\left(-\ln(1+x^2)\right) = \dfrac1{1+x^2}$

Multiply both sides of the equation by 1/(1 + x²) :

$\dfrac1{1+x^2} y' - \dfrac{2x}{(1+x^2)^2} y = 0$

and observe that

d/dx[1/(1 + x²)] = -2x/(1 + x²)²

Then

$\left(\dfrac1{1+x^2}y\right)' = 0$

$\dfrac1{1+x^2}y = C$

$y = C(1 + x^2)$

When x = 0, y = 3, so

$3 = C(1+0^2) \implies C=3$

$\implies \boxed{y = 3(1 + x^2) = 3 + 3x^2}$

7 0

2 years ago

Please help me it's urgent!

Crank

Answer:

y = 2x-5

y=-x+4

Step-by-step explanation:

Just need to solve the:

x+y=4

y-2x=-5

And we have:

x=3

y=1

Then replace x and y into the answer to find the correct one

7 0

3 years ago

Can y’all help me please I need help

Illusion [34]

Answer:

503 inches (rounded to the nearest whole number)

Step-by-step explanation:

First, we must calculate the wheel's circumference, or in other words, the distance around the wheel. We can do this by using the below equation:

$C=\pi d$ when $d$ is the diameter

Because we know that the wheel's diameter is 16 inches, we can plug it into the equation:

$C=\pi (16)\\C=16\pi$

Now, because we know that the wheel makes 10 revolutions, we calculate the distance it travelled by multiplying the circumference by 10.

$16\pi *10\\= 160\pi$

$= 503$ inches when rounded to a whole number

Therefore, the wheel travelled approximately 503 inches.

I hope this helps!

8 0

3 years ago

Subtract. Write your answer as a fraction in simplest form.<br><br> 5/8 - (-7/8)= ???

Doss [256]

The answer has a mixed reaction is 1 1/2 but as an improper fraction is it 3/2!

8 0

3 years ago