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3 years ago

Find the rule for the following set of data.

Mathematics

2 answers:

Olenka [21]3 years ago

8 0

Answer:

$y = \frac{5}{2} x + 2$

Step-by-step explanation:

Find slope which is also referred to as m:

m = (y2 - y1) / (x2 - x1)

= 7-12 / 2 - 4

= -5 / -2

= 5/2

y = mx + b

17 = 5/2(6) + b

17 = 15 + b

b = 2

y = 5/2x + 2

Ne4ueva [31]3 years ago

7 0

Answer:

Step-by-step explanation:

I think it's five but if it isn't then I will donate your points back:)

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Step-by-step explanation:

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3 years ago

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What is the value of 8 plus (27 divided by 9) power of two

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Answer:

8+ (27/9)2 = 17

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3 years ago

Please help with this

Paraphin [41]

Answer:

x = 5

Step-by-step explanation:

The sides are in proportion.

The proportion is 20/36

The other sides must be in the same proportion: 5x / 45

5x/45 = 20/36 You can reduce the left side by dividing top and bottom by 5

1x / 9 = 20/36 You can reduce the right side by dividing by 4

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That is the answer.

However you can extend this by cross multiplying

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x = 45/9

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3 years ago

Which of the following is irrational?

uysha [10]

Answer
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2 years ago

I need to know the improper fractions answers for:

zmey [24]

Answer:

Part 1) $x=\frac{15}{2}\ units$

Part 2) $z=\frac{15\sqrt{3}}{2}\ units$

Part 3) $y= \frac{15\sqrt{3}}{4}\ units$

Part 4) $b= \frac{45}{4}\ units$

Step-by-step explanation:

step 1

Find the value of x

In the large right triangle

$cos(60^o)=\frac{x}{15}$ ----> by CAH (adjacent side divided by the hypotenuse)

Remember that

$cos(60^o)=\frac{1}{2}$

substitute

$\frac{1}{2}=\frac{x}{15}$

solve for x

$x=\frac{15}{2}\ units$ ---> improper fraction

step 2

Find the value of z

In the large right triangle

Applying the Pythagorean Theorem

$15^2=x^2+z^2$

substitute the value of x

$15^2=(\frac{15}{2})^2+z^2$

solve for z

$z^2=15^2-(\frac{15}{2})^2$

$z^2=225-\frac{225}{4}$

$z^2=\frac{675}{4}$

$z=\frac{\sqrt{675}}{2}\ units$

simplify

$z=\frac{15\sqrt{3}}{2}\ units$

step 3

Find the value of y

In the right triangle of the right

$sin(30^o)=\frac{y}{z}$ ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$sin(30^o)=\frac{1}{2}$

$\frac{1}{2}=y:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{1}{2}= \frac{2y}{15\sqrt{3}}$

$y= \frac{15\sqrt{3}}{4}\ units$

step 4

Find the value of b

In the right triangle of the right

$cos(30^o)=\frac{b}{z}$ ---> by CAH (adjacent side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$cos(30^o)=\frac{\sqrt{3}}{2}$

$\frac{\sqrt{3}}{2}=b:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{\sqrt{3}}{2}= \frac{2b}{15\sqrt{3}}$

$b= \frac{45}{4}\ units$

7 0

3 years ago