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daser333 [38]
3 years ago
14

Find the rule for the following set of data.

Mathematics
2 answers:
Olenka [21]3 years ago
8 0

Answer:

y = \frac{5}{2} x + 2

Step-by-step explanation:

Find slope which is also referred to as m:

m = (y2 - y1) / (x2 - x1)

   = 7-12 / 2 - 4

   = -5 / -2

   = 5/2

y = mx + b

17 = 5/2(6) + b

17 = 15 + b

b = 2

y = 5/2x + 2

Ne4ueva [31]3 years ago
7 0

Answer:

5?

Step-by-step explanation:

I think it's five but if it isn't then I will donate your points back:)

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Answer:

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Step-by-step explanation:

correct answer for edge 2020

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3 years ago
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What is the value of 8 plus (27 divided by 9) power of two
saw5 [17]

Answer:

8+ (27/9)2 = 17

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3 years ago
Please help with this
Paraphin [41]

Answer:

x = 5

Step-by-step explanation:

The sides are in proportion.

The proportion is 20/36

The other sides must be in the same proportion: 5x / 45

5x/45 = 20/36        You can reduce the left side by dividing top and bottom by 5

1x / 9 = 20/36          You can reduce the right side by dividing by 4

x / 9 = 5/9                at this point you should be able to see that x = 5, because the denominators are the same.

That is the answer.

However you can extend this by cross multiplying

9x = 45                      Divide by 9

x = 45/9

x = 5

5 0
3 years ago
Which of the following is irrational?
uysha [10]
Answer
<span>C. root 3 + 8.486</span>
7 0
2 years ago
I need to know the improper fractions answers for:
zmey [24]

Answer:

Part 1) x=\frac{15}{2}\ units

Part 2) z=\frac{15\sqrt{3}}{2}\ units

Part 3) y= \frac{15\sqrt{3}}{4}\ units

Part 4) b= \frac{45}{4}\ units

Step-by-step explanation:

step 1

Find the value of x

In the large right triangle

cos(60^o)=\frac{x}{15} ----> by CAH (adjacent side divided by the hypotenuse)

Remember that

cos(60^o)=\frac{1}{2}

substitute

\frac{1}{2}=\frac{x}{15}

solve for x

x=\frac{15}{2}\ units ---> improper fraction

step 2

Find the value of z

In the large right triangle

Applying the Pythagorean Theorem

15^2=x^2+z^2

substitute the value of x

15^2=(\frac{15}{2})^2+z^2

solve for z

z^2=15^2-(\frac{15}{2})^2

z^2=225-\frac{225}{4}

z^2=\frac{675}{4}

z=\frac{\sqrt{675}}{2}\ units

simplify

z=\frac{15\sqrt{3}}{2}\ units

step 3

Find the value of y

In the right triangle of the right

sin(30^o)=\frac{y}{z} ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values of y and z

Remember that

sin(30^o)=\frac{1}{2}

so

\frac{1}{2}=y:\frac{15\sqrt{3}}{2}

solve for y

\frac{1}{2}= \frac{2y}{15\sqrt{3}}

y= \frac{15\sqrt{3}}{4}\ units

step 4

Find the value of b

In the right triangle of the right

cos(30^o)=\frac{b}{z} ---> by CAH (adjacent side divided by the hypotenuse)

substitute the given values of y and z

Remember that

cos(30^o)=\frac{\sqrt{3}}{2}

so

\frac{\sqrt{3}}{2}=b:\frac{15\sqrt{3}}{2}

solve for y

\frac{\sqrt{3}}{2}= \frac{2b}{15\sqrt{3}}

b= \frac{45}{4}\ units

7 0
3 years ago
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