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daser333 [38]
4 years ago
14

Find the rule for the following set of data.

Mathematics
2 answers:
Olenka [21]4 years ago
8 0

Answer:

y = \frac{5}{2} x + 2

Step-by-step explanation:

Find slope which is also referred to as m:

m = (y2 - y1) / (x2 - x1)

   = 7-12 / 2 - 4

   = -5 / -2

   = 5/2

y = mx + b

17 = 5/2(6) + b

17 = 15 + b

b = 2

y = 5/2x + 2

Ne4ueva [31]4 years ago
7 0

Answer:

5?

Step-by-step explanation:

I think it's five but if it isn't then I will donate your points back:)

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What is the value of q − 7 if q = −17?
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Answer:

-24

Step-by-step explanation:

-7 - 17 = -24.

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Can u plz tell me what is 22=-11n
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n=-2

Step-by-step explanation:

22=-11n

u divide it and u get

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Which of the following expressions is a factor of the polynomial x2+3/2x-1?
mafiozo [28]

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Choose the function whose graph is given by:
Sophie [7]

Answer:

C.y=sin(x-2)

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Using the topic of transformation of functions(rules shown in picture above)

the the (x-2) moves the graph to places to the right

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hope it helps!! :)

5 0
2 years ago
Q4<br> Help pleaseeeeeeee
emmasim [6.3K]

a. The general equation for a circle centered at (a,b) with radius r is

(x-a)^2+(y-b)^2=r^2

The described circle has equation

(x+3)^2+(y+2)^2=r^2

We know the circle passes through the origin. This means that the equation above holds for x=0 and y=0. The distance between any point on the circle and its center is the radius, so we can use this fact to determine r:

(0+3)^2+(0+2)^2=r^2\implies 9+4=13=r^2\implies r=\sqrt{13}

So the circle's equation is

(x+3)^2+(y+2)^2=(\sqrt{13})^2=13

b. If the distance between point B and the center is less than \sqrt{13}, then B lies inside the circle. If the distance is greater than \sqrt{13}, it falls outside the circle. Otherwise, if the distance is exactly \sqrt{13}, then B lies on the circle.

The distance from B to the center is

\sqrt{(-1+3)^2+(3+2)^2}=\sqrt{4+25}=\sqrt{29}

29>13, so \sqrt{29}>\sqrt{13}, which means B falls outside the circle.

5 0
3 years ago
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