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Yanka [14]
3 years ago
12

Please help. no body ever helps right away. i’ll mark brainlist and give thanks. geometry btw

Mathematics
1 answer:
Bess [88]3 years ago
6 0

9514 1404 393

Answer:

  437.3 ft

Step-by-step explanation:

The angle of depression can be copied inside the triangle to the angle of elevation (at lower right). Then the side x can be seen to be adjacent to the angle.

The mnemonic SOH CAH TOA reminds you of the relations. Here, we have the hypotenuse and we want the adjacent angle. The relevant relation is ...

  Cos = Adjacent/Hypotenuse

  cos(29°) = x/(500 ft)

Multiplying by 500 ft gives ...

  x = (500 ft)cos(29°)

  x ≈ 437.3 ft

_____

<em>Additional comment</em>

You have posted a number of problems that make use of this geometry. They are all solved the same way:

  a) identify the desired measure and the given measures

  b) using SOH CAH TOA, identify the relation applicable to those measures

  c) fill in the given values in the equation

  d) solve for the unknown

You may need to make use of what you know about angles and triangles in order to relate given angles to ones you need to use.

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Step-by-step explanation:

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Tonya is staring a jewelry business. She is going to sell b bracelets for $12.50 each and n necklaces for $22.50. Tonya wants to
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Answer:

C 12.50b+22.50n≥800

Step-by-step explanation:

Tonya is staring a jewelry business. She is going to sell b bracelets for $12.50 each and n necklaces for $22.50. Tonya wants to make at least $800 a month.

When we use the word at least in Mathematics is means that it is equal to or more than $800.

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Number of necklaces = n

Therefore, the inequality below models this situation is given as:

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3 0
3 years ago
Largest perfect square of 250
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Answer:

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Step-by-step explanation:

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6 0
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A manufacturing process that produces electron tubes is known to have a 10% defective rate. Suppose a random sample of 15 tubes
posledela

Answer:

Probability of obtaining no more than two defective tubes = 0.816

Step-by-step explanation:

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Further explanations and calculations are given in the attachment below:

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