Answer:
x=y=z=90.
Step-by-step explanation:
let the 3 numbers be x,y,z.
let s be sum
s=x+y+z
we need to maximize xy+yz+zx
or , xy + y(270-(x+y))+x(270-(x+y)) = P(x)
Use Lagrange's Multipliers
⇒ΔP= λΔS
⇒
⇒y=x
⇒\frac{x+z}{x+y} =1
⇒z=y
⇒x=y=z
⇒3x = 270
⇒x= 90
hence, x=y=z=90.
Answer: The range is y ≥ 3.
Step-by-step explanation:
When we have an equation:
y = f(x)
The range is the set of the possible values of y.
In this case, we have:
y = f(x) = 2*x^2 - 20*x + 53
This is a quadratic equation, and the leading coefficient is positive. This means that the arms of the graph will open upwards.
Then the minimum value of y will be the vale at the vertex.
We know that for a quadratic equation of the form:
a*x^2 + b*x + c
The vertex is at:
x = -b/2a
Then in this case, the vertex will be at:
x = -(-20)/(2*2) = 20/4 = 5
Then the smallest value of this function will be:
f(5) = 2*5^2 - 20*5 + 53 = 3
This is the smallest value that y can take, and y can take any value greater than 3.
Then the range can be written as:
y ≥ 3.
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Answer:
The smallest is 14.
Step-by-step explanation:
Let the numbers be x, x+2 and x+4, then:
x + x + 2 + x + 4 = 48
3x + 6 = 48
3x = 42
x = 14.
So the 3 numbers are 14, 16 and 18.