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2 years ago

GIVING BRAINLIEST TO WHOEVER ANSWERS THIS ASAP PLSSSS

Mathematics

2 answers:

kotegsom [21]2 years ago

7 0

The second one

Just think LxWxH

Ivanshal [37]2 years ago

5 0

Answer:

I think its the second one

Step-by-step explanation:

Im sorry if im wrong tho

You might be interested in

Which statement about quadrilateral LAMB is true?

den301095 [7]

Quadrilateral LAMB is a parallelogram because opposite sides are parallel.

<h3>Quadrilateral</h3>

A quadrilateral is a polygon with four sides and four angles. Types of quadrilaterals are<em> square, rectangle, kite, parallelogram, rhombus a</em>nd so on.

A parallelogram is a quadrilateral in which opposite sides are opposite and parallel to each other.

Quadrilateral LAMB is a parallelogram because opposite sides are parallel.

Find out more on Quadrilateral at: brainly.com/question/16691874

8 0

2 years ago

41. What is the image of O(- 3, - 2) after two reflections, first across the line y = - 5 , then across the line x = 1 ? (1 poin

liberstina [14]

Answer:

D(5,-8)

Step-by-step explanation:

The given point is (-3,-2)

When we reflect in the line y=k, we use the rule (x, 2k-y)

This implies that:

$(-3, - 2)\to (-3, 2*-5--2)$

$(-3, - 2)\to (-3, - 8)$

When we reflect in the line x=k, we use the rule

$(x,y)\to (2k-x,y)$

Now we have x=1

This implies that:

$( - 3, - 8)\to (2 \times 1- - 3, - 8)$

$( - 3, - 8)\to (5, - 8)$

4 0

3 years ago

Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

5 0

3 years ago

Gwen, Tristan, and Keith like to work out at the gym. They each have an app on their phone that estimates the calories they burn

aleksandrvk [35]

Answer:

Part A:

Gwen has already burned 100 calories when Tristan and Keith started, and he continues to burn 10 calories per minute. The equation for Gwen is

y = 100 + 10x

Part B:

Tristan is burning 125 calories every 10 minutes. His burning calories rate is 12.5 calories per minute. The equation for Tristan is

y = 12.5x

Part C:

Keith is burning 300 calories in 30 minutes. His rate per minute is 10 calories per minute. The equation for Keith is

y = 10x

Part D:

Just follow the instructions and do the thing for the app. You can then answer the questions it is very easy.

Part E:

Do the same for E after you do Part D.

Step-by-step explanation:

Hope it helps!

6 0

3 years ago

Read 2 more answers

I NEED HELP W THIS QUESTION ASAP

zloy xaker [14]

Answer:

Step-by-step explanation:

This is a little tricky. You have to read it a couple of times to sort out the numbers.

She wants 12 servings for 5 people. She has 10 people. That means she needs 12*2 = 24 servings in all for the 10 people.

If she has pans that hold 8 servings and she requires 24 servings then she needs 24 / 8 = 3 pans.

The answer is C.

5 0

3 years ago