How will a high outlier in a data set affect the mean and median?

Mathematics

1 answer:

RUDIKE [14]3 years ago

5 0

Answer:

B. distribution skewed to the right, mean pulled to the right, median not effected

Step-by-step explanation:

When a distribution is skewed to the right, it means that the data is positively skewed or has more positive numbers than negative numbers.

An outlier can affect the mean of a distribution since a high value outlier will make the mean be much higher than the median. In this case, since the distribution is positively skewed, a high outlier will pull the mean to the right (to higher positive values).

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The city airport and the train station are 45 miles apart. there are 9 gas stations equally spaced between the airport and train

Zielflug [23.3K]

The distance between the two adjacent gas stations will be 5 miles.

<h3>What is the difference between a ratio and a proportion?</h3>

A ratio is an ordered pair of integers a and b expressed as a/b, with b never equaling 0. A percentage is a mathematical expression in which two ratios are specified to be equal.

Distance between city airport and the train station = 45 miles

Stations equally spaced between the airport and train station=9

Let the space between two gas stations will be x;

x = 45/9

x=5 mile.

Hence, the distance between the two adjacent gas stations will be 5 miles.

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2 years ago

What does the median represent in a set of numbers?

Alja [10]

Answer:

The median is the middle number in a sorted, ascending or descending, list of numbers and can be more descriptive of that data set than the average. The median is sometimes used as opposed to the mean when there are outliers in the sequence that might skew the average of the values.

Step-by-step explanation:

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5 0

3 years ago

Write a polynomial of degree 5 with zero x=0,i square root 7, -2i

professor190 [17]

Answer:

$P(x)=x^5+11x^3+28x$

Step-by-step explanation:

<u>Roots of a polynomial</u>

If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula

$P(x)=a(x-x_1)(x-x_2)(x-x_3)...(x-x_n)$

Where a is an arbitrary constant.

We know three of the roots of the degree-5 polynomial are:

$x_1=0;\ x_2=\sqrt{7}\boldsymbol{i}:\ x_3=-2\boldsymbol{i}$

We can complete the two remaining roots by knowing the complex roots in a polynomial with real coefficients, always come paired with their conjugates. This means that the fourth and fifth roots are:

$x_4=-\sqrt{7}\boldsymbol{i}:\ x_3=+2\boldsymbol{i}$