I think it's consistent and independent because consistent means it has at least one solution (which it does) and independent means that it has exactly one solution. (i wasnt familiar with these terms so i googled what they meant, i apologise in advance if i am wrong)
I know I dislike it as well! Sorry you are having trouble with it! :)
20.15625 is the answer to your question if you would like the method you move the percentage two decimal places and multiply.
Answer:
2x to the second power +x−10
Step-by-step explanation:
Let's simplify step-by-step.
5x+x2−4−(4x−x2+6)
Distribute the Negative Sign:
=5x+x2−4+−1(4x−x2+6)
=5x+x2+−4+−1(4x)+−1(−x2)+(−1)(6)
=5x+x2+−4+−4x+x2+−6
Combine Like Terms:
=5x+x2+−4+−4x+x2+−6
=(x2+x2)+(5x+−4x)+(−4+−6)
=2x2+x+−10
ez copy pasta
XZ ≅ EG and YZ ≅ FG is enough to make triangles to be congruent by HL. Option b is correct.
Two triangles ΔXYZ and ΔEFG, are given with Y and F are right angles.
Condition to be determined that proves triangles to be congruent by HL.
<h3>What is HL of triangle?</h3>
HL implies the hypotenuse and leg pair of the right-angle triangle.
Here, two right-angle triangles ΔXYZ and ΔEFG are congruent by HL only if their hypotenuse and one leg are equal, i.e. XZ ≅ EG and YZ ≅ FG respectively.
Thus, XZ ≅ EG and YZ ≅ FG are enough to make triangles congruent by HL.
Learn more about HL here:
brainly.com/question/3914939
#SPJ1
In ΔXYZ and ΔEFG, angles Y and F are right angles. Which set of congruence criteria would be enough to establish that the two triangles are congruent by HL?
A.
XZ ≅ EG and ∠X ≅ ∠E
B.
XZ ≅ EG and YZ ≅ FG
C.
XZ ≅ FG and ∠X ≅ ∠E
D.
XY ≅ EF and YZ ≅ FG
