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netineya [11]
3 years ago
8

A. What is the change in internal energy for each of the following situations? q = 7.9 J out of the system and w = 3.6 J done on

the system q = 1.5 J into the system and w = 7.5 J done on the system
Physics
1 answer:
Orlov [11]3 years ago
4 0

Answer: -4.3\ J,\ 9\ J

Explanation:

Given

(a)

Heat transfer Q=-7.9\ J\quad \text{taken}

Work done W=-3.6\ J\quad \text{on the system}

Change in the internal kinetic energy is

\Delta U=Q-W\\\Rightarrow \Delta U=-7.9-(-3.6)\\\Rightarrow \Delta U=-4.3\ J

(b)

Heat transfer Q=1.5\ J\quad \text{given}

Work done W=-7.5\ J\quad \text{on the system}

Change in the internal kinetic energy is

\Delta U=Q-W\\\Rightarrow \Delta U=1.5-(-7.5)\\\Rightarrow \Delta U=9\ J

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Given that,

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\dfrac{\Delta P}{\Delta T}=\dfrac{\Delta H}{T\Delta V}

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\dfrac{1000\times10^{5}}{\Delta T}=\dfrac{13050}{(1085+273)\times(8.0-7.6)\times10^{-6}}

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