Incomplete question as the mass of baseball is missing.I have assume 0.2kg mass of baseball.So complete question is:
A baseball has mass 0.2 kg.If the velocity of a pitched ball has a magnitude of 44.5 m/sm/s and the batted ball's velocity is 55.5 m/sm/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat.
Answer:
ΔP=20 kg.m/s
Explanation:
Given data
Mass m=0.2 kg
Initial speed Vi=-44.5m/s
Final speed Vf=55.5 m/s
Required
Change in momentum ΔP
Solution
First we take the batted balls velocity as the final velocity and its direction is the positive direction and we take the pitched balls velocity as the initial velocity and so its direction will be negative direction.So we have:

Now we need to find the initial momentum
So

Substitute the given values

Now for final momentum

So the change in momentum is given as:
ΔP=P₂-P₁
![=[(11.1kg.m/s)-(-8.9kg.m/s)]\\=20kg.m/s](https://tex.z-dn.net/?f=%3D%5B%2811.1kg.m%2Fs%29-%28-8.9kg.m%2Fs%29%5D%5C%5C%3D20kg.m%2Fs)
ΔP=20 kg.m/s
The sciences concerned with the study of inanimate natural objects, including physics, chemistry, astronomy, and related subjects.
Answer:
The magnitude of the voltage is
and the direction of the current is clockwise.
Explanation:
Given that,
Number of turns = 9
Magnetic field = 0.5 T
Diameter = 3 cm
Time t = 0.14 s
We need to calculate the flux
Using formula of flux

Put the value into the formula


We need to calculate the emf
Using formula of emf




Negative sign shows the direction of current.
Hence, The magnitude of the voltage is
and the direction of the current is clockwise.
An electron has a negative charge
A gram molecule<span> of a </span>gas<span> at </span>127<span>°C </span>expands isothermally until its volume<span> is </span>doubled<span>. </span>Find<span> the </span>amount<span>of </span>work done<span> and </span>heat absorbed<span>.</span>