Answer:
x₁ = 0.1878 m
Explanation:
For this exercise we will use conservation of energy
starting point. Highest point
Em₀ = U = m g h
final point. Lowest point with fully compressed spring
Em_f = K_e + U
Em_f = ½ K x² + m g x
energy is conserved
Em₀ = Em_f
m g h = ½ K x² + m g x
½ K x² + mg (x- h) = 0
let's substitute
½ 7.3 x² + 0.030 9.8 (x- 0.25) = 0
3.65 x² + 0.294 (x- 0.25) = 0
x² + 0.080548 (x- 0.25) = 0
x² - 0.020137 + 0.080548 x = 0
x² + 0.080548 x - 0.020137 = 0
let's solve the quadratic equation
x = [0.080548 ±√ (0.080548² + 4 0.020137)] / 2
x = [0.080548 ± 0.29502] / 2
x₁ = 0.1878 m
x₂ = -0.1072 m
These are the compression and extension displacement of the spring
Answer:
It produces 1000Ω.
Explanation:
You have to apply Voltage formula, V = I × R :
V = I × R
6 = 0.006 × R
R = 6 ÷ 0.006
R = 1000Ω
According to Newton's third law of motion, "The single ball on the left will move as high as the ball on the right was dropped" is the expected result once the ball hits the ball closest to it.
Answer: Option A
<u>Explanation:</u>
Newton’s cradle is the best example for law of conservation of momentum. So that means that energy or momentum exhibited by a particle can be transferred to its nearer object with equal force. So in the given options the first option is correct. As when the right ball is dropped it will collide with its neighboring ball and transfer energy.
By this transferring of energy from one particle to another, it will reach the leftmost ball. But there will be no loss in the energy as the left ball will move as high position as the ball on the right was dropped from. So that means the energy is conserved in the cradle.
Step 1 : Get your supply list together
Step 2 : Pick what model you want to do
Step 3 : Ask for a partner
Step 4 : Complete the model and take your time.
Step 5 : Read the directions carefully
Acceleration = change in velocity / time
change in velocity = final velocity - initial velocity
because the object is slowing down, the acceleration will be negative.
acceleration = (4-34) / 60
acceleration = -30 / 60
acceleration = -0.5 m/s^2
answer : the train is accelerating at -0.5 m/s^2