Answer:
-5 m/s²
Explanation:
Acceleration = change in velocity / change in time
a = (v − v₀) / (t − t₀)
a = (-0.4 m/s − 0.6 m/s) / 0.2 s
a = -5 m/s²
The ball decelerates at a rate of -5 m/s².
use consevation of linear momentum
- m1v1+m2v2=(M1+M2)V3
- 281(2.82)+209(-1.72)=(209+281)V2
- 792.42-359.48=490v3
- 432.9=490v3
- V3=0.88m/s
Answer:
The options are not provided, so i will answer in a general way.
We know that:
The movement is along a straight horizontal surface, then we have one-dimensional motion.
The speed is 2m/s
We want a graph of position vs time.
Now, remember the relation:
Distance = Speed*Time
Then we can write the position as a function of time as:
P(t) = 2m/s*t + P0
Where t is our variable, that represents time in seconds, and P0 is the position at time t = 0seconds, we can assume that this is zero.
Then the equation is:
P(t) = 2m/s*t
And the graph is something like:
Explanation:
This how you do it..
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There’s no picture so how r we supposed to answer it