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kherson [118]
3 years ago
12

A jogger runs 5.0 km on a straight trail at an angle of 60° south of west. What is the southern component of the run rounded to

the nearest tenth of a kilometer?
Physics
2 answers:
harkovskaia [24]3 years ago
8 0

Answer:

The work for the previous answer is correct, however, since the final velocity is in the southward direction, the answer is -4.3.

Explanation:

Edgenuity will tell you this is the correct answer as well.

liberstina [14]3 years ago
6 0
60 ° is the angle between W- direction and the run direction.

You need the angle betwee S-direction and the run direction. This is 90° - 60° = 30 °.

By geometry you can trace a right triangle, where the S-component is the adyacent side and the run  is the hypotenuse.

Then cos 30° = adyacent side / hypotenuse = S-component / run

Then S-component = run * cos 30° = 5.0 km * 0.866 = 4.3 km

Answer: 4.3 km
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How are metals identified i the periodic table??
zaharov [31]

Answer:

okay here is a thing I learned when I was younger in my middle school:

Explanation:

my teacher would tell me that metals are considered a weak metals are on the left side and the good metals are located on the right side because the only way I remembered was the right means it is really strong and the left is weak and not that supportive. but I think that's how I still think it is or other people may have their own opinions. but hope this helped out with your question!

8 0
3 years ago
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You are walking along a small country road one foggy morning and come to an intersection. While you are crossing, you hear an am
emmainna [20.7K]

Answer:

64.945 miles per hour

Explanation:

Since the frequency of sound heard is higher than actual frequency, the ambulance is moving towards you!

The frequency of sound waves as heard from a distance for a sound wave coming towards one at v₀ m/s and whose real frequency is f₀ is given by

+f = f₀/[1 - (v₀/v)]

+f = frequency of sound as heard from the distance away = 8.61 KHz

f₀ = real frequency of sound = 7.87 KHz

v₀ = velocity at which the sound source is moving towards the reference point = ?

v = velocity of sound waves = 343 m/s

8.61 = 7.87/(1 - (v₀/v))

1 - (v₀/343) = 0.9141

v₀/343 = 1 - 0.9141 = 0.0859

v₀ = 343 × 0.0859 = 29.48 m/s = 64.945 miles per hour

7 0
3 years ago
How much force (in Newtons) acts on a 1700 kg car going around a
Daniel [21]

Answer:

b) 4781 N

Explanation:

Because there is a redius do this question is talking about the acceleration force which= mv^2/r

so a=15^2/80=2.8125 m^2/s

so the force will be = m.a

F =1700×2.8125=4781.25 N

5 0
2 years ago
Filiberto va a 90m/s en su carri, de repente se distrae por un par de segundos y su velocdad pasa a 40 m/s ¿cual fue su acelerac
svet-max [94.6K]

Answer:

Filiberto experimenta una deceleración de 2\,\frac{m}{s^{2}}.

Explanation:

(The problem was written in Spanish. Hence, explanation will be held in Spanish).

Asúmase que Filiberto se distrae por 2 segundos, puesto que un par equivale a dos, y que el vehículo experimenta un aceleración constante. La deceleración experimentada por el vehículo se deriva de la siguiente fórmula:

a = \frac{v-v_{o}}{\Delta t}

a = \frac{40\,\frac{m}{s}-90\,\frac{m}{s} }{2\,s}

a = -25\,\frac{m}{s^{2}}

Filiberto experimenta una deceleración de 2\,\frac{m}{s^{2}}.

7 0
3 years ago
Twice each each lunar month, all year long, these tides occur. Whenever the Moon, Earth and Sun are aligned, the gravitational p
Zarrin [17]

That was a lucky pick.

Twice each each lunar month, all year long, whenever the Moon,
Earth and Sun are aligned, the gravitational pull of the sun adds
to that of the moon causing maximum tides.

This is the setup at both New Moon and Full Moon.  It doesn't matter
whether the Sun and Moon are both on the same side of the Earth,
or one on each side.  As long as all three bodies are lined up, we
get the biggest tides.

These are called "spring tides", when there is the greatest difference
between high and low tide.

At First Quarter and Third Quarter, when the sun, Earth, and Moon form a
right angle, there is the least difference between high and low tide.  Then
they're called "neap tides".
4 0
2 years ago
Read 2 more answers
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