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Vikentia [17]
2 years ago
7

Can someone help me solve for x and show the work please

Mathematics
1 answer:
Elden [556K]2 years ago
7 0

Answer:

D. -10

Step-by-step explanation:

The sum of a triangle = 180°, therefore,

64° + 63° + x + 63 = 180°

Add like terms

x + 190° = 180°

Subtract 190 from each side

x + 190 - 190 = 180 - 190

x = -10

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Jobisdone [24]

Answer:

387 km

Step-by-step explanation:

The length of AC, b can be obtained using the cosine rule ; using the cosine relation:

b² = a² + c² - 2ac CosB

b² = 250² + 185² - 2(250*185) Cos125

b² = 62500 + 34225 - 92500 * −0.573576

b² = 96725 + 53055.820

b² = 149780.82

b = sqrt(149780.82)

b = 387.01527

b = 387 km (nearest whole number)

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2 years ago
the appalachian trail is a 2,155-mile hiking trail in the eastern United states. You plan to hike the section of the trail that
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Step-by-step explanation:

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4 0
3 years ago
Find an equation of the plane that contains the points p(5,−1,1),q(9,1,5),and r(8,−6,0)p(5,−1,1),q(9,1,5),and r(8,−6,0).
topjm [15]
Given plane passes through:
p(5,-1,1), q(9,1,5), r(8,-6,0)

We need to find a plane that is parallel to the plane through all three points, we form the vectors of any two sides of the triangle pqr:
pq=p-q=<5-9,-1-1,1-5>=<-4,-2,-4>
pr=p-r=<5-8,-1-6,1-0>=<-3,5,1>

The vector product pq x pr gives a vector perpendicular to both pq and pr.  This vector is the normal vector of a plane passing through all three points
pq x pr
=
  i   j   k
-4 -2 -4
-3  5  1
=<-2+20,12+4,-20-6>
=<18,16,-26>

Since the length of the normal vector does not change the direction, we simplify the normal vector as
N = <9,8,-13>

The required plane must pass through all three points.
We know that the normal vector is perpendicular to the plane through the three points, so we just need to make sure the plane passes through one of the three points, say q(9,1,5).

The equation of the required plane is therefore
Π :  9(x-9)+8(y-1)-13(z-5)=0
expand and simplify, we get the equation
Π  :  9x+8y-13z=24

Check to see that the plane passes through all three points:
at p: 9(5)+8(-1)-13(1)=45-8-13=24
at q: 9(9)+8(1)-13(5)=81+9-65=24
at r: 9(8)+8(-6)-13(0)=72-48-0=24
So plane passes through all three points, as required.

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