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aev [14]
3 years ago
7

Please help me, thank you in advance :)

Mathematics
1 answer:
7nadin3 [17]3 years ago
8 0

Answer:

dont know the ans but thank God trump is out of the office sorry for wasting ur time

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The cross-section of a square pyramid will be a square.  The section above the cross-section taken will basically be a similar but smaller square pyramid.  D is the correct answer.
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HELP COLLEGE ALGEBRA
max2010maxim [7]

Answer:

1) \frac{-8}{11}  

2) 1.276

3) \frac{3}{4}

4) 0

Step-by-step explanation:

The slope formula of the line that pass across two points P1(x1,y1) and P2(x2,y2) is:

\frac{y2 - y1}{x2-x1} = slope

You can use this formula to solve all the four points:

1)

\frac{6- -2}{-9 - 2} = \frac{-8}{11}

2)

\frac{- 9.1 - 0.6}{-9.5 - - 1.9} = \frac{97}{76} =(Rounded)= 1.276

3)

\frac{2-5}{-2 -2} = \frac{3}{4}

4)

\frac{4-4}{-9 --4} = \frac{0}{-5} = 0 \\\\

3 0
3 years ago
Two functions are combined resulting in the function j(x) = –3x2 + 5.
labwork [276]

Answer:

two quadratic functions combined by addition

a linear function and a quadratic function combined by addition

two linear functions combined by multiplication

Step-by-step explanation:

-3x² + 5

(-4x² + 4) + (x² + 1)

-3x² + 5

(-3x² - x) + (x + 5)

-3x² + 5

(sqrt(5) - sqrt(3)x)(sqrt(5) + sqrt(3)x)

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3 years ago
A class of 32 students is organised in 33 teams every team consists of 3 students and there are no identical teams . show that t
Tresset [83]

Answer:

Step-by-step explanation:

Let's start by making up as many teams as we can with the 32 student. Given that each team is different, we can make 10 teams of 3 each. (we still have 23 more teams to make).

The last two people make a team of only 2. No matter which student from the 30 other students is picked, the team of two and the one the student is coming from will have one student in common. Though there are more borrowings that take place (many more), the results remain as stated. At least 2 teams will have 1 person in common.

The method is called the pigeon hole method.

6 0
4 years ago
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