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4 years ago

Simplify 83. 24 192 512

Mathematics

2 answers:

loris [4]4 years ago

8 0

83 is a prime
24 = 2³x3
192 = 2⁶x3
256 = 2⁸

Anna71 [15]4 years ago

8 0

Answer: The answer is 512. Have a blessed day! :)

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Determine the polynomial equivalent to this expression.

gregori [183]

Answer:

$\dfrac{x^2-9}{x-3}= \Large \boxed{x+3}$

Step-by-step explanation:

Hello,

We need to work a little bit of the expression to see if we can simplify.

Do you remember this formula?

for any a and b reals, we can write

$a^2-b^2=(a-b)(a+b)$

We will apply it.

For any x real number different from 3 (as dividing by 0 is not allowed)

$\dfrac{x^2-9}{x-3}=\dfrac{x^2-3^2}{x-3}=\dfrac{(x-3)(x+3)}{x-3}=x+3$

So the winner is C !!

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0

3 years ago

The sum of two numbers is 46 and the difference is 10 . What are the numbers?

valina [46]

Answer: 28 and 18

Step-by-step explanation:

I used the guess and test strategy to find that:

28 - 10 = 18

28 + 18 = 46

7 0

3 years ago

Read 2 more answers

Hi, does anyone know how to solve this. If so, please show the working out too. Thanks.

sergiy2304 [10]

See the explanation

<h2>Explanation:</h2><h2 />

I have corrected your diagram so ∅ is the angle at the top of the diagram. In order to solve this problem we have to use Pythagorean theorem and the law of sines. Moreover, I have named two sides as w and z so those variables will help us to solve this problem. So:

The triangle at the bottom is right, so by Pythagorean theorem is true that:

$w^2=4^2+(2\sqrt{2})^2 \\ \\ w^2=24 \\ \\ w=\sqrt{24} \\ \\ w=2\sqrt{6}$

By law of sines:

$\frac{z}{sin\theta}=\frac{w}{sin60^{\circ}} \\ \\ z=\frac{wsin\theta}{sin60^{\circ}} \\ \\ z=\frac{2\sqrt{6}sin\theta}{\sqrt{3}/2} \\ \\ z=4\sqrt{2}sin\theta$

By law of sines again:

$\frac{y}{sin45^{\circ}}=\frac{z}{sin\phi} \\ \\ y=\frac{zsin45^{\circ}}{sin\phi} \\ \\ y=\frac{4\sqrt{2}sin\theta \sqrt{2}/2}{sin\phi} \\ \\ \\ Finally: \\ \\ \boxed{y=\frac{4sin\theta}{sin\phi}}$