5) The relation between intensity and current appears linear for intensity of 300 or more (current = intensity/10). For intensity of 150, current is less than that linear relation would predict. This seems to support the notion that current will go to zero for zero intensity. Current might even be negative for zero intensity since the line through the points (300, 30) and (150, 10) will have a negative intercept (-10) when current is zero.
Usually, we expect no output from a power-translating device when there is no input, so we expect current = 0 when intensity = 0.
6) We have no reason to believe the linear relation will not continue to hold for values of intensity near those already shown. We expect the current to be 100 for in intensity of 1000.
8) Apparently, times were only measured for 1, 3, 6, 8, and 12 laps. The author of the graph did not want to extrapolate beyond the data collected--a reasonable choice.
finish the question
Step-by-step explanation:
Answer:
width=20m,length=23m
Step-by-step explanation:
as shown in the figure which is attached
let width of pool =x
⇒ length of pool=x+3
width of walk =2
⇒width of outer boundary of walk=x+4 (2 on each side of pool)
length of outer boundary of walk=x+3+4=x+7
area of pool =x×(x+3)
area of walk+pool=(x+4)×(x+7)
given
total area of the pool and walk is 188 square meters more than the area of the pool
⇒(x+4)×(x+7)=188+x×(x+3)
⇒8x=160
x=20m
dimensions of pool
widh=20m
length=20+3=23m
Answer:
7th grade math help me pleasee
- + - + respectively 1234
