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nata0808 [166]
3 years ago
11

Which numbers are rational?

Mathematics
1 answer:
Otrada [13]3 years ago
4 0
All numbers except for the square root of 50
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4 1/3 · 3/5 express your answer in simplest form. A. 2 3/5 B. 2 C. 4 1/5 D. 1 1/15
a_sh-v [17]

Oh the answer is a I looked it up this time

7 0
3 years ago
Read 2 more answers
Triangle PQR is transformed to triangle P'Q'R'. Triangle PQR has vertices P(4, 0), Q(0, −4), and R(−8, −4). Triangle P'Q'R' has
Whitepunk [10]

Answer:

Please find attached the required plot accomplished with an online tool

Part A:

1/4

Part B:

P''(-1, 0),  Q''(0, -1), and R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent

Step-by-step explanation:

Part A:

Triangle ΔPQR has vertices P(4, 0), Q(0, -4), R(-8, -4)

Triangle ΔP'Q'R' has vertices P'(1, 0), Q'(0, -1), R'(-2, -1)

The dimensions of the sides of the triangle are given by the relation;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Where;

(x₁, y₁) and (x₂, y₂) are the coordinates on the ends of the segment

For segment PQ, we place (x₁, y₁) = (4, 0) and (x₂, y₂) = (0, -4);

By substitution into the length equation, we get;

The length of segment PQ = 4·√2

The length of segment PR = 4·√10

The length of segment RQ = 8  

The length of segment P'Q' = √2

The length of segment P'R' = √10

The length of segment R'Q' = 2

Therefore, the scale factor of the dilation of ΔPQR to ΔP'Q'R' is 1/4

Part B:

Reflection of (x, y) across the y-axis gives;

(x, y) image after reflection across the y-axis = (-x, y)

The coordinates after reflection of P'(1, 0), Q'(0, -1), R'(-2, -1) across the y-axis is given as follows;

P'(1, 0) image after reflection across the y-axis = P''(-1, 0)

Q'(0, -1) image after reflection across the y-axis = Q''(0, -1)

R'(-2, -1) image after reflection across the y-axis = R''(2, -1)

Part C:

Triangle PQR is similar to triangle P''Q''R'' but they are not congruent as the dimensions of the sides of triangle PQR and P''Q''R'' are not the same.

6 0
3 years ago
What is the answer to this problem
Aleks04 [339]

Answer:

14 cm^2

Step-by-step explanation:

You find the area of both triangles, and subtract by 4

6x3x1/2x2 - 2x2

18 - 4

14

3 0
3 years ago
I wasn't in class so I need help solving the inequality 7/10n+14<49
NikAS [45]

Answer:

n<50

Step-by-step explanation:

7/2*5n + 14<49

7n/2*5+14<49

(7n)+(2*5)14/2*5 <49

7n+10*14/2*5 <49

7n+140/2*5 <49

7n+140/10 <49

7n+140 < 10*49

7n+140 < 490

(7n+140)+(-140)<490+(-140)

7n+140-140<490-140

7n<350

7n/7 < 350/7

n<2*5^2*7/7

n<2*5^2

n<2*25

n<50

8 0
3 years ago
X² – 2x - 15 / x² - 6x+5
Nuetrik [128]

Answer:

all work is pictured/shown

7 0
3 years ago
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