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Elina [12.6K]
3 years ago
12

Can u help me with this one

Mathematics
1 answer:
koban [17]3 years ago
7 0

Answer:

SU = 16

Step-by-step explanation:

SU= 8x

ST = 6x

TU = 4

SU = ST + TU = 6x + 4 = 8x

SU - ST = 8x - 6x = 2x = 4

2x = 4

x = 4/2

x = 2

SU = 8x

SU = 8(2)

SU = 16

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The perimeter of a playing card is 30 centimeters. The playing card is 5 centimeters wide. How tall is it?
Sidana [21]

Answer:

(I think) it's 10 cms because total perimeter is 30 centimeters so there will be 5 on two sides making 10,30-10=20 and 20/2=10 which makes a total of 30 (5+5+10+10)

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2 years ago
A right triangle has side lengths 7, 24, and 25 as shown below.
Hoochie [10]

Answer: Tan B = 0.2917 (16.26 degrees)

Sin B = 0.2800 (16.26 degrees)

Cos B = 0.9600 (16.26 degrees)

Step-by-step explanation: Please refer to the picture attached for details.

The right angled triangle LNB has been drawn with the sides labeled as 7, 24 and 25 as indicated. With angle B as the reference angle, we can now identify each side as follows;

Side 7 (opposite, facing the reference angle)

Side 24 (adjacent, between the reference angle and the right angle)

Side 25 (hypotenuse, facing the right angle).

Hence, using the trigonometric ratios,

Tan B = opposite/adjacent

Tan B = 7/24

Tan B = 0.2917 (16.26 degrees)

Sin B = opposite/hypotenuse

Sin B = 7/25

Sin B = 0.2800 (16.26 degrees)

Cos B = adjacent/hypotenuse

Cos B = 24/25

Cos B = 0.9600 (16.26 degrees)

3 0
4 years ago
Name the ray in the figure
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Find the three angles of the triangle with the given vertices: P(1,1,1), ????(1,−3,2), and ????(−3,2,5).
velikii [3]

Answer:

The three angles of the triangle are 90, 35.67 and 54.33 degrees.

Step-by-step explanation:

One way to find the angles of the triangle with vertices (1, 1, 1), (1, -3, 2), (-3, 2, 5) is using the definition of the <em>dot product</em> of two vectors, defined as:

a . b = |a| |b| cosФ [1]

Where |a| and |b| are the norms of vectors <em>a</em> and b, and cosФ is the cosine of the angle between either vector <em>a</em> and <em>b</em>.

If a = [ \\ a_{1}, a_{2}, a_{3} ] and b = [\\ b_{1}, b_{2}, b_{3}], then the dot product is simply a number (not a vector) obtained from:

a . b = \\ a_{1}*b_{1} + a_{2}*b_{2} + a_{3}*b_{3}

The norm of a vector (its length) is, for instance, |a| = \\ \sqrt{{a_{1}^2 + {a_{2}}^2 + {a_{3}}^2}, for a vector in \\ R^{3}.

Having all that into account, we can determine the angles of the triangle for each vertex using equation [1] and solving it for Ф.

<h3>Angle of the triangle for vertex in (1, 1, 1)</h3>

The vectors which form an angle from this vertex are the result of subtracting the vertex (1, 1, 1) to any of the remaining points (1, -3, 2) and (-3, 2, 5):

v(1, 1, 1) - v(1, -3, 2) = \\ (1 - 1, 1 - (-3), 1 - 2) = (0, 1 + 3, -1) = (0, 4, -1)

v(1, 1, 1) - v(-3, 2, 5) = \\ (1 - (-3), 1 - 2, 1 - 5) = (1 + 3, -1, -4) = (4, -1, -4)

The <em>dot product</em> for these vectors is:

[0, 4, -1] . [4, -1, -4] = [0 * 4 + 4 * -1 + -1 * -4] = 0 - 4 + 4 = 0

The norm for each vector is:

|(0, 4, -1)| = \\ \sqrt{0^2 + 4^2 + -1^2} = \sqrt{0 + 16 + 1} = \sqrt{17}

|(4, -1, -4)| = \\ \sqrt{4^2 + -1^2 + -4^2} = \sqrt{16 + 1 + 16} = \sqrt{33}

So

a . b = |a| |b| cosФ

\\ 0 = \sqrt{17} * \sqrt{33} * cos{\theta}

\\ \frac{0}{\sqrt{17} * \sqrt{33}} = cos{\theta}

\\ cos^{-1}{0}} = cos^{-1}(cos{\theta})

\\ 90 = \theta

In vertex (1, 1, 1) the angle of the triangle is 90 degrees. We have here a right triangle.

We have to follow the same procedure for finding the vectors for angles in vertices (1, -3, 2) and (-3, 2, 5), or better, after finding one of the previous angles, we find the remaining angle subtracting the sum of two angles from 180 degrees to finally obtaining the three angles in question.

Therefore, the other angles are 35.67 degrees and 180 - (90 + 35.67) = 180 - 125.67 = 54.33 degrees.

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The answer is 10. Apex :)

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