3 years ago

What is the ratio for Cos C?

Mathematics

1 answer:

Sedaia [141]3 years ago

3 0

Answer:

$Cos(C) = \frac{40}{41}$

Step-by-step explanation:

Ratio of Cos C using the trigonometric ratios formula, would be:

$Cos(C) = \frac{adjacent}{hypotenuse}$

Adjacent = BC = 40

Hypotenuse = AC = 41

Plug in the values

$Cos(C) = \frac{40}{41}$

You might be interested in

What is the equation of the described circle? A) (x − 2)2 + (y + 3)2 = 58 B) (x − 2)2 + (y + 3)2 = 68 Eliminate C) (x + 2)2 + (y

SIZIF [17.4K]

Answer:

Step-by-step explanation:

8 0

3 years ago

Identify the excluded values of this product. Then rewrite the product in simplest form.

lara [203]

$\frac{6 {y}^{2} + 18y - 60 }{3 {y}^{2} - 12y } \times \frac{ {y}^{2} - 16 }{ {y}^{2} + 2y - 8} \\ \\ \frac{ {6y + 30y - 12y - 60}^{2} }{3y(y - 4)} \times \frac{ {(y)}^{2} - ( {4)}^{2} }{ {y}^{2} + 4y - 2y - 8 } \\ \\ \frac{6y(y + 5) - 12(y + 5)}{3y(y - 4)} \times \frac{(y + 4)(y - 4)}{y(y + 4) - 2(y + 4)} \\ \\ \frac{(6y - 12)(y + 5)}{3y(y - 4)} \times \frac{(y + 4)(y - 4)}{(y + 4)(y - 2)} \\ \\ \frac{6(y - 2)(y + 5)}{3y(y - 2)} \\ \\ \frac{2(y + 5)}{y} .$