LuAnn is playing a math game. She chooses three cards. The value of

An airplane is traveling at a speed of 240 miles/hour with a bearing of 110°. The wind velocity is 56 miles/hour at a bearing of

vodka [1.7K]

Answer:

Actual speed = 288 miles per hour

Actual direction angle = $116.38^\circ$

Step-by-step explanation:

"Bearing" is the relative position of an object outside the plane compared to the position of the plane.

Heading the the direction the nose of the plane is pointing.

Course is the direction that pilot wants the plane to go.

Wind direction is always the direction the wind is blowing from.

The airplane is traveling at a speed of 240 miles/hour with a bearing of 110°.

If the plane is traveling with a bearing of 110° and the wind is blown at a bearing of 325°.

$325^{\circ}- 110^{\circ} =225^{\circ}$

$215^{\circ}- 180^{\circ} =35^{\circ}$

The Ground speed will be in excess of the airspeed and true direction will be south if the indicated heading.

The tailwind component is:

$56 cos (35^\circ)$

And the cross wind component is:

$56 sin (35^\circ)$

And that is,

$C^2 = (286)^2 + (32)^2$

$c = 288$

So the actual speed of the plane is 288 miles per hour.

The deviation in the direction is:

Let the direction angle be 'x'.

$x = tan ^{-1}\left ( \frac{32}{286} \right )=6.38^\circ$

So the actual direction angle is $110^\circ+ 6.38^\circ=116.38^\circ$ .

5 0

3 years ago

A circle has a radius of 5. Express in term of pi the circumference of the circle

Natalka [10]

Circumference of a circle = 2pir
2pi(5) = 10pi

3 0

3 years ago

Help please look at picture supplementary angles

8_murik_8 [283]

Answer:

x=16

Step-by-step explanation:

....,...................

5 0

3 years ago

Pleasssssssseeee help

astra-53 [7]

Rates like $ per channel is a slope, "m". The added fee is a constant so it's the intercept "b".
y = mx + b

So for the first problem (9)
(a)
y = total cost in dollars
x = number of premium channels
y = 16x + 44
(b) when x = 3 channels
y = 16(3) + 44
y = 92 $

the second problem (10)
(a) every 4 years the tree grows by 12-9=3 ft
So the unit rate or slope will be 3 ft per 4 yrs, (3/4). You can see this also by solving for slope "m" using the given points (4,9) and (8,12).

x = number of years
y = height of tree in ft
y = (3/4)x + b
use one of the points to find the y-intercept "b".

9 = (3/4)(4) + b
9 = 3 + b
9 - 3 = b
6 = b
y = (3/4)x + 6

(b) when x = 16
y = (3/4)(16) + 6
y = 12 + 6
y = 18 ft

5 0

4 years ago

(x +y)^5 Complete the polynomial operation

Vesna [10]

Answer:

Please check the explanation!

Step-by-step explanation:

Given the polynomial

$\left(x+y\right)^5$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=x,\:\:b=y$

$=\sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i$

so expanding summation

$=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$

solving

$\frac{5!}{0!\left(5-0\right)!}x^5y^0$

$=1\cdot \frac{5!}{0!\left(5-0\right)!}x^5$

$=1\cdot \:1\cdot \:x^5$

$=x^5$

also solving

$=\frac{5!}{1!\left(5-1\right)!}x^4y$

$=\frac{5}{1!}x^4y$

$=\frac{5x^4y}{1}$

$=5x^4y$

similarly, the result of the remaining terms can be solved such as

$\frac{5!}{2!\left(5-2\right)!}x^3y^2=10x^3y^2$

$\frac{5!}{3!\left(5-3\right)!}x^2y^3=10x^2y^3$

$\frac{5!}{4!\left(5-4\right)!}x^1y^4=5xy^4$

$\frac{5!}{5!\left(5-5\right)!}x^0y^5=y^5$

so substituting all the solved results in the expression

$=\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$

$=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$

Therefore,

$\left(x\:+y\right)^5=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$

6 0

3 years ago