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GuDViN [60]
3 years ago
5

Answers the question please

Mathematics
1 answer:
Kruka [31]3 years ago
6 0

Answer:

I would say (B) 14,55

Step-by-step explanation:

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I need to figure out if I'm doing this correctly
kogti [31]

To prove that triangles TRS and SUT are congruent we can follow these statements:

1.- SR is perpendicular to RT: Given

2.-TU is perpendicular to US: Given

3.-Angle STR is congruent with angle TSU: Given.

4.-Reflexive property over ST: ST is congruent with itself (ST = ST)

From here, we can see that both triangles TRS and SUT have one angle of 90 degrees, another angle that they both have, and also they share one side (ST) ,then:

5.- By the ASA postulate (angle side angle), triangles TRS and SUT are congruent

5 0
1 year ago
a road follows the shape of a parabola f(x)=3x2– 24x + 39. A road that follows the function g(x) = 3x – 15 must cross the stream
Nonamiya [84]

the coordinates where the bridges must be built is (3,-6) and (6,3) .

<u>Step-by-step explanation:</u>

Here we have , a road follows the shape of a parabola f(x)=3x2– 24x + 39. A road that follows the function g(x) = 3x – 15 must cross the stream at point A and then again at point B. Bridges must be built at those points.We need to find Identify the coordinates where the bridges must be built. Let's find out:

Basically we need to find values of x for which f(x) = g(x) :

⇒ f(x)-g(x)=0

⇒ 3x^2- 24x + 39-(3x - 15 ) =0

⇒ 3x^2- 24x + 39-3x + 15  =0

⇒ 3x^2- 27x + 54  =0

⇒ x^2- 9x + 18  =0

⇒ x^2- 6x-3x + 18  =0

⇒ x(x- 6)-3(x - 6)  =0

⇒ (x-3)(x- 6)  =0

⇒ x=3 , x=6

Value of g(x) at x = 3 : y=3x -15 = 3(3)-15 = -6

Value of g(x) at x = 6 : y=3x -15 = 3(6)-15 = 3

Therefore , the coordinates where the bridges must be built is (3,-6) and (6,3) .

7 0
4 years ago
What is the value of the expression 3–4?  <br>A.–81  <br>B.–12  <br>C.–   <br>D.
Arturiano [62]
Calculate  3-4 = -1 that is the value
4 0
3 years ago
Pls anwser this math questions number 11 and 12 both it’s easy !
sp2606 [1]

I think C would be for number 11

A is for 12.

x/2 < - 18

7 0
3 years ago
Determine the probability of landing on tails at most 33 times if you flip a fair coin 80 times. Round your answer to the neares
grigory [225]

Answer:

0.0728177272

Step-by-step explanation:

Given :

Number of flips = 80

Probability of landing on tail at most 33 times ;

Probability of landing on tail on any given flip = 1 / 2 = 0.5

This a binomial probability problem:

Hence ;

P(x ≤ 33) = p(x=0) + p(x=1) +... + p(x = 33)

Using a binomial probability calculator :

P(x ≤ 33) = 0.0728177272

7 0
3 years ago
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