Given: ABCD is a trapezoid, m∠1=m∠2, m∠3=m∠4, AB = CD, AC ∩ BD = O
Prove: m∠AOD = m∠BCD
1 answer:
Since AB = CD the trapezoid is isosceles, which means that ∡A = ∡D
Therefore also ∡2 = ∡3 (they are half of the congruent angles)
For the properties of parallel lines (BD and AD) crossed by a transversal (BD) we have ∡3 = ∡CBD.
Now consider triangles AOD and BCD:
∡OAD (2) = ∡ADO (3) = ∡CBD (3) = ∡CDB (4)
T<span>he sum of the angles of a triangle must be 180°, t</span>herefore:
∡AOD = 180 - ∡2 - ∡3
∡BCD = 180 - ∡3 - ∡4
∡AOD = ∡BCD because their measure is the difference of congruent angles.
You might be interested in
Answer:
y = 3, y = 5, y = -1
Step-by-step explanation:
What you do is you substitute the x values into the x.
<em>y + 2(-1) = 5</em>
<em>y + -2 = 5</em>
y = 3
<em>y + 2(0) = 5</em>
y = 5
<em>y + 2(4) = 5</em>
<em>y + 6 = 5</em>
y = -1.
Answer:
For 3.99 each ounce is 12 cents an ounce while the 48 ounce is 10 cents an ounce. So I think it would be the 48 ounce please mark brainliest
Answer:
I believe that would be 12 because
Step-by-step explanation:
if 2x - 7y = 10
then if you were to add two to that it would be 12
