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Daniel [21]
3 years ago
14

Pints quarts cups gallons from most precise to least precise

Mathematics
1 answer:
Keith_Richards [23]3 years ago
4 0
Least to greatest: cups, pints, quarts, gallons
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Express 8.5454545454... as a rational number, in the form p/q where p and q are positive integers with no common factors.
zzz [600]
x=8.\overline{54}\\
100=854.\overline{54}\\
100x-x=854.\overline{54}-8.\overline{54}\\
99x=846\\
x=\dfrac{846}{99}=\dfrac{94}{11}


5 0
3 years ago
Round your answer to the nearest hundredth . B+21 3/8=4/7​
NemiM [27]

Answer:

Step-by-step explanation:

B= -20+45/56

B=-20.80

3 0
4 years ago
The number by which the dividend is being divided? Means?
Ann [662]
That would be called the quotient.
7 0
3 years ago
Read 2 more answers
The Office of Student Services at a large western state university maintains information on the study habits of its full-time st
Vera_Pavlovna [14]

Answer:

0.8254 = 82.54% probability that the mean of this sample is between 19.25 hours and 21.0 hours

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 20 hours, standard deviation of 6:

This means that \mu = 20, \sigma = 6

Sample of 150:

This means that n = 150, s = \frac{6}{\sqrt{150}}

What is the probability that the mean of this sample is between 19.25 hours and 21.0 hours?

This is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19.5. So

X = 21

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{21 - 20}{\frac{6}{\sqrt{150}}}

Z = 2.04

Z = 2.04 has a p-value of 0.9793

X = 19.5

Z = \frac{X - \mu}{s}

Z = \frac{19.5 - 20}{\frac{6}{\sqrt{150}}}

Z = -1.02

Z = -1.02 has a p-value of 0.1539

0.9793 - 0.1539 = 0.8254

0.8254 = 82.54% probability that the mean of this sample is between 19.25 hours and 21.0 hours

3 0
3 years ago
When using blocking to deal with extraneous factors in an experiment, the
Elena L [17]

Answer:

<em>False</em>

Step-by-step explanation:

took the test

6 0
3 years ago
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