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Rufina [12.5K]
3 years ago
10

Solve 2x + 2 > 10A. x<6B. x>6C. x>4D. x<4​

Mathematics
1 answer:
melamori03 [73]3 years ago
4 0
The answer is c) x>4
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Can someone help please??????
denis23 [38]

Answer:

Please refer to the attachment

8 0
3 years ago
0.85 km/s = ___ m/min
Lelechka [254]
To convert km/s to m/min, multiply by 1000*60=60000

hence 0.85km/s=51000 m/min
5 0
3 years ago
Please solve and show work! Thanks!
notsponge [240]

Answer:

1) x < 1, x > 9

2) 2 < x ≤ 6, -4 ≤ x < 0

Step-by-step explanation:

1) lx - 5l > 4

x - 5 = 4

x = 9

-(x - 5) = 4

x = -4 + 5 = 1

x < 1, x > 9

3) 1 < lx-1l ≤ 5

1 < x-1 ≤ 5

2 < x ≤ 6

1 < -(x-1) ≤ 5

-5 ≤ x-1 < -1

-4 ≤ x < 0

6 0
2 years ago
Read 2 more answers
Rahima goes jogging on a course that is 2.75kilometers long. If she completes the full course every morning, how many kilometers
Arada [10]

Answer:

<h2>19.25km</h2>

Step-by-step explanation:

Step one:

given data

we are told that the distance that Rahima covers on a daily is 2.75km long

we also know that a week has 7 days that is Mon-Sunday

Required

the total distance for a week

Step two:

Hence the total distance covered for  7 days is

=2.75*7

=19.25km

<em>Simply multiply the distance covered in a day by 7 to get the distance covered in a week </em>

6 0
2 years ago
Read 2 more answers
A tank in the shape of an inverted right circular cone has height 7 meters and radius 2 meters. It is filled with 5 meters of ho
iren [92.7K]

Answer:

The work required to empty the tank is 1,580,887 J

Step-by-step explanation:

Work = mass of chocolate × acceleration due to gravity × height of chocolate

Volume of tank (cone) = 1/3πr^2h = 1/3 × 3.142 × 2^2 × 7 = 29.33 m^3

Mass of hot chocolate = density of hot chocolate × volume of cone = 1100 kg/m^3 × 29.33 m^3 = 32,263 kg

height of chocolate = 5 m

Work = 32,263×9.8×5 = 1,580,887 J

3 0
2 years ago
Read 2 more answers
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